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Jlenok [28]
3 years ago
5

One effect of some refrigerant gases in the atmosphere is that they:

Chemistry
1 answer:
Elden [556K]3 years ago
7 0

Deplete the ozone layer

or

Act as greenhouse gases


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Which substances are made up of polymers? DNA , a glass bottle , ice crystals , the proteins in hair , rubber car tires.
lana66690 [7]

Answer:

proteins in hair

Explanation:

proteins are polymers of amino acids. so if proteins are polymers of amino acids it means that proteins in hair are made of polymers

6 0
3 years ago
What would happen if our atmosphere consisted of pure oxygen
aleksklad [387]
Things would burn much easily because oxygen is flammable 
7 0
3 years ago
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Cual de los estados de agregacion es mas abundante en el universo
alisha [4.7K]

Answer: El Plasma, es el estado físico mas abundante no solo del universo sino de la naturaleza:

Explanation:

"El plasma es el estado de agregación más abundante de la naturaleza, y la mayor parte de la materia en el Universo visible se encuentra en estado de plasma, la mayoría del cual es el enrarecido plasma intergaláctico (particularmente el medio del intracluster) y en las estrellas."

7 0
3 years ago
he equilibrium constant, Kc , for the following reaction is 7.00×10-5 at 673 K.NH4I(s) NH3(g) + HI(g)If an equilibrium mixture o
frosja888 [35]

<u>Answer:</u> The number of moles of HI in the solution is 1.24\times 10{-3} moles.

<u>Explanation:</u>

We are given:

K_c=7.00\times 10^{-5}\\n_{NH_3}=0.405mol\\n_{NH_4I}=1.45mol\\V=4.90L

To calculate the concentration of a substance, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     ......(1)

  • Concentration of ammonia:

[NH_3]=\frac{0.405mol}{4.90L}=0.083mol/L

  • Concentration of ammonium iodide:

[NH_4I]=\frac{1.45mol}{4.90L}=0.30mol/L

For the given chemical reaction:

NH_4I(s)\rightleftharpoons NH_3(g)+HI(g)

The expression of K_c for above equation follows:

K_c=\frac{[HI][NH_3]}{[NH_4I]}

Putting values in above equation, we get:

7.0\times 10^{-5}=\frac{[HI]\times 0.083}{0.30}

[HI]=2.53\times 10^{-4}

Calculating the moles of hydrogen iodide by using equation 1, we get:

2.53\times 10^{-5}=\frac{\text{Moles of HI}}{4.9}\\\\\text{Moles of HI}=1.24\times 10^{-3}

Hence, the number of moles of HI in the solution is 1.24\times 10{-3} moles.

3 0
3 years ago
3 Points
svp [43]

Answer:

C. Splitting the atom

Explanation:

splitting the atom involves fission

4 0
3 years ago
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