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melomori [17]
3 years ago
6

A 3-phase, 50 Hz, 110 KV overhead line has conductors placed in a horizontal plane 3 m apart. Conductor diameter is 2.5 cm. If t

he line length is 220 km, determine the charging current per phase assuming complete transposition. (6 Marks)
Engineering
1 answer:
Bas_tet [7]3 years ago
6 0

Answer:

A 3-phase, 50 Hz, 110 KV overhead line has conductors

Explanation:

hope it will helps you

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The acceleration of a point is given. a = 20 t m/s2 When t=0, s = 50 m and v = -8 m/s. What are the position and velocity of the
lidiya [134]

Answer:

v=82 m/s

s=116m

Explanation:

a=20t

\frac{\mathrm{d} v}{\mathrm{d} t}=20t\\\int\limits dv =\int(20t) dt\\v={10}t^2+c

using condition given at t=0

-8=10\times 0^2 +c

c=-8

now equation becomes

v=10t²-8

v at t= 3s  v=82 m/s

again

\frac{\mathrm{d} s}{\mathrm{d} t}=10t^2-8

ds=(10t^2-8)dt\\\int\limits ds =\int(10t^2-8) dt\\s=\frac{10}{3} t^2-8t+b

now using condition given s=50 at t=0

b=50

now equation becomes

s=\frac{10}{3}t^3-8t+50

calculating s at t=3s

s=116m

6 0
3 years ago
(25) Consider the mechanical system below. Obtain the steady-state outputs x_1 (t) and x_2 (t) when the input p(t) is the sinuso
sammy [17]
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5 0
3 years ago
for high-volume production runs, machining parts from solid material might not be the best choice of manufacturing operations be
Naddik [55]

Answer:

There are actually multiple types of processes a manufacturer uses, and those can be grouped into four main categories: casting and molding, machining, joining, and shearing and forming.

Explanation:

8 0
3 years ago
While there are many ways to solve this problem, one strategy is to calculate the volume of any metal's unit cell given its theo
IgorC [24]

Answer:

V_{c}=1.396x10^{-28}  m^{3} /unit.cell

Explanation:

z = number of atoms

M = Molar mass of zirconium

N = Avogadro’s number

Vc = volume of zirconium unit cell

d = density

z=12x\frac{1}{6}+2x\frac{1}{2}+3=6

z = 6 atoms per unit cell

M = 91.224 g/mol

N = 6.023x10^{23}  atoms/mol

d = 6.51g/cm^{3}

V_{c}=\frac{zxM}{dxN}

V_{c}=\frac{6x(91.224g/mol)}{(6.51g/cm^{3}) x(6.023x10^{23}atoms/mol) }

V_{c}=1.396x10^{-22}  cm^{3} /unit.cell

V_{c}=1.396x10^{-28}  m^{3} /unit.cell

8 0
3 years ago
Describe the algorithm you use for looking up a person’s telephone number in the phone book. The input is person’s name; the out
Stella [2.4K]

Answer:

The Algorithm for finding a number from a phone book with the person's name as the input and the phone number as output is as follows:

1. Try to remember the name, i.e last name first and first name last, Also make sure you get the spelling right.

2. Using the first letter of the last name, locate the appropriate alphabetical section in which the name should appear.

3. Using the second letter of the last name, find the subsection of first and second letters combined, in the appropriate order, in which the name should appear. (If the last name consists of only two letters, find the appropriate first name.)

4. Using the third letter, find the possible names in a subsection of the first three letters in the correct order. Continue this step with x+1 letters of the name until you have a subsection of names exactly matching the last name of the person whose number you are trying to locate. (x is the number of letters used in the previous step, consistently.) If there is only one of the last name, (check for duplicates) identify the number, and return phone number information.

5. Begin the second step using the first letter of the first name, but limit the section to only those exactly matching the last name. Continue to step 4, again focusing on the first name only within the set of exactly matching last names.

6. When both first and last name match the name you are locating, check for duplicates. IF there are no duplicates, return phone number information.

Explanation:

People's names are generally arranged in phone books in alphabetical order by the last name of the person. The first name of the person is listed after the last name so that people of the same last name can be differentiated.

7 0
3 years ago
Read 2 more answers
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