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Free_Kalibri [48]
3 years ago
11

A triply charged ion with velocity 7.00 × 10^6 m/s moves in a path of radius 36.0 cm in a magnetic field of 0.55 T in a mass spe

ctrometer. What is the mass of this ion?
Physics
1 answer:
saw5 [17]3 years ago
6 0

Answer:

Mass of ion will be 22\times 10^{-13}kg                

Explanation:

We have given ion is triply charged that is q=3\times 1.6\times 10^{-19}=4.8\times 10^{-19}C

Radius r = 36 cm = 0.36 m

Velocity of the electron v=7\times 10^6m/sec

Magnetic field B = 0.55 T

We know that radius of the path is given by r=\frac{mv}{qB}

m=\frac{rqB}{v}=\frac{0.36\times 4.8\times 10^{-19}\times 7\times 10^6}{0.55}=22\times 10^{-13}kg

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The tension in the rope is constant and equal to 40 N as the block is pulled. What is the instantaneous power (in W) supplied by
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Complete Question:

A 10 kg block is pulled across a horizontal surface by a rope that is oriented at 60° relative to the horizontal surface.

The tension in the rope is constant and equal to 40 N as the block is pulled. What is the instantaneous power (in W) supplied by the tension in the rope if the block when the block is 5 m away from its starting point? The coefficient of kinetic friction between the block and the floor is 0.2 and you may assume that the block starting at rest.

Answer:

Power = 54.07 W

Explanation:

Mass of the block = 10 kg

Angle made with the horizontal, θ = 60°

Distance covered, d = 5 m

Tension in the rope, T = 40 N

Coefficient of kinetic friction, \mu = 0.2

Let the Normal reaction = N

The weight of the block acting downwards = mg

The vertical resolution of the 40 N force, f_{y} = 40sin \theta

\sum f(y) = 0

N + 40 sin \theta - mg = 0\\N = -40sin60 + 10*9.81 = 0\\N = 63.46 N

\sum f(x) = 0

40 cos 60 - f_{r} - ma = 0\\ f_{r} = \mu N\\ f_{r} = 0.2 * 63.46\\ f_{r} = 12.69 N\\40cos 60 - 12.69-10a = 0\\7.31 = 10a\\a = 0.731 m/s^{2}

v^{2}  = u^{2} + 2as\\u = 0 m/s\\v^{2}  =  2 * 0.731 * 5\\v^{2}  = 7.31\\v = \sqrt{7.31} \\v = 2.704 m/s

Power, P = Fvcos \theta

P = 40 *2.704 cos60\\P = 54.074 W

7 0
3 years ago
A block of mass 10 kg slides down an inclined plane that has an angle of 30. If the inclined plane has no friction and the block
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No friction present means: Ek = Ep

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A guyot is ________. A. any portion of the ocean floor that is topographically higher than surrounding sea floor B. an extinct o
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Answer:

c.an extinct oceanic hot-spot volcano that has subsided below sea level

Explanation:

- Marine geology defines a guyot as an isolated underwater volcanic mountain with a flat top more than 200m below the surface of the sea.

-The flat top is due to years of wave erosion.

-Guyots can form a chain of seamounts as the ocean plate of the Earth's crust moves slowly over a hot spot that remains stationary beneath the plate.

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What is the mass of an object that is hanging 12.6 m above the surface of the earth and has a
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Answer:

22.05 Kg

Explanation:

Apply the formula:

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2778.3 = 10 . Mass . 12.6

2778.3 = 126 . Mass

Mass = 2778.3/126

Mass = 22.05

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3 years ago
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