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Gnoma [55]
3 years ago
6

an airplane is moving with a constant velocity in level flight. compare the magnitude of the forward force by the engines to the

magnitude of the backward frictional drag force.
Physics
1 answer:
Iteru [2.4K]3 years ago
5 0

The two forces are equal in magnitude

Explanation:

We can answer this question by applying Newton's second law of motion, which states that

\sum F = ma

where

\sum F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, the airplane is moving with constant velocity, so its acceleration is zero:

a = 0

This means that the equation becomes

\sum F = 0

There are two forces acting on the airplane in the horizontal direction:

- The forward force exerted by the engine, F

- The frictional drag force, D, backward

So the net force on the plane along the horizontal direction is

\sum F = F-D

However we also said that

\sum F = 0

Combining the two equations, we find

F-D=0 \rightarrow F=D

So, the two forces have same magnitude.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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