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Gnoma [55]
3 years ago
6

an airplane is moving with a constant velocity in level flight. compare the magnitude of the forward force by the engines to the

magnitude of the backward frictional drag force.
Physics
1 answer:
Iteru [2.4K]3 years ago
5 0

The two forces are equal in magnitude

Explanation:

We can answer this question by applying Newton's second law of motion, which states that

\sum F = ma

where

\sum F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, the airplane is moving with constant velocity, so its acceleration is zero:

a = 0

This means that the equation becomes

\sum F = 0

There are two forces acting on the airplane in the horizontal direction:

- The forward force exerted by the engine, F

- The frictional drag force, D, backward

So the net force on the plane along the horizontal direction is

\sum F = F-D

However we also said that

\sum F = 0

Combining the two equations, we find

F-D=0 \rightarrow F=D

So, the two forces have same magnitude.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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2. A carpenter tosses a shingle off a 9.4 m high roof, giving it an initial horizontal
Aleksandr [31]

Sounds like the shingle/ball is thrown from the roof horizontally, so that the distance it travels <em>x</em> after time <em>t</em> horizontally is

<em>x</em> = (7.2 m/s) <em>t</em>

The object's height <em>y</em> at time <em>t</em> is

<em>y</em> = 9.4 m - 1/2 <em>gt</em>²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity, and its vertical velocity is

<em>v</em> = -<em>gt</em>

(a) The object hits the ground when <em>y</em> = 0:

0 = 9.4 m - 1/2 <em>gt</em>²

<em>t</em>² = 2 * (9.4 m) / (9.80 m/s²)

<em>t</em> ≈ 1.92 s

at which time the object's vertical velocity is

<em>v</em> = -<em>g</em> (1.92 s) = -18.8 m/s ≈ -19 m/s

(b) See part (a); it takes the object about 1.9 s to reach the ground.

(c) The object travels a horizontal distance of

<em>x</em> = (7.2 m/s) * (1.92 s) ≈ 13.8 m ≈ 14 m

8 0
3 years ago
A bug splats against the windshield of a car traveling at high speeds down a backcountry road. Which statement correctly compare
zvonat [6]

Answer:

C. The bug's change in momentum is equal to the car's change in momentum.

Explanation:

As we know by Newton's 2nd law

F = \frac{\Delta P}{\Delta t}

here we have also know that when car hits the bug then force applied by wind shield on the bug is same as the force applied by the bug on the car's wind shield as per Newton's III law

F_{12} = F_{21}

so we know that

\frac{\Delta P_{12}}{\Delta t} = \frac{\Delta P_{21}}{\Delta t}

so we have

\Delta P_{12} = \Delta P_{21}

so correct answer will be

C. The bug's change in momentum is equal to the car's change in momentum.

6 0
4 years ago
Which statement about velocity is true?
LekaFEV [45]

Answer:

Velocity has both speed and direction. Speed is constant. ... Speed is measured over time.

Explanation:

8 0
3 years ago
Add the vectors:
Anettt [7]

Vector 1 has components

x_1=(10\,\mathrm m)\cos20^\circ\approx9.40\,\mathrm m

y_1=(10\,\mathrm m)\sin20^\circ\approx3.42\,\mathrm m

and vector 2 has

x_2=(10\,\mathrm m)\cos80^\circ\approx1.74\,\mathrm m

y_2=(10\,\mathrm m)\sin80^\circ\approx9.85\,\mathrm m

Add these vectors to get the resultant, which has components

x_{\rm total}\approx11.133\,\mathrm m

y_{\rm total}\approx13.268\,\mathrm m

The magnitude of the resultant is

\sqrt{{x_{\rm total}}^2+{y_{\rm total}}^2}\approx17.321\,\mathrm m

with direction \theta such that

\tan\theta=\dfrac{y_{\rm total}}{x_{\rm total}}\implies\theta\approx50^\circ

or about 50º N of E.

8 0
3 years ago
17.a car is traveling at a constant velocity of 60 km/h for 4 hours means
Setler [38]
<span>Assuming the car is travelling in the same direction for the entire hour, the acceleration is zero.</span>
7 0
3 years ago
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