Answer:
Height is 11.25m
Explanation:
<u>Given the following data;</u>
Initial velocity, u = 0
Final velocity, v = 15m/s
Acceleration due to gravity, g = 10m/s²
To find the height, we would use the third equation of motion;
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
- S represents the displacement (height) measured in meters.
<em>Making S the subject, we have;</em>
![S = \frac {V^{2} - U^{2}}{2a}](https://tex.z-dn.net/?f=%20S%20%3D%20%5Cfrac%20%7BV%5E%7B2%7D%20-%20U%5E%7B2%7D%7D%7B2a%7D)
But a = g = 10m/s²
<em>Substituting into the equation, we have;</em>
![S = \frac {225}{20}](https://tex.z-dn.net/?f=%20S%20%3D%20%5Cfrac%20%7B225%7D%7B20%7D)
S = 11.25m
<em>Therefore, the ball will reach a height of 11.25m before it begins to fall. </em>
We can see the axon as a current-carrying wire. The magnetic field produced by a current-carrying wire is given by
![B(r) = \frac{\mu_0 I}{2 \pi r}](https://tex.z-dn.net/?f=B%28r%29%20%3D%20%20%5Cfrac%7B%5Cmu_0%20I%7D%7B2%20%5Cpi%20r%7D%20)
where
![\mu_0 = 4 \pi \cdot 10^{-7} Tm/A](https://tex.z-dn.net/?f=%5Cmu_0%20%3D%204%20%5Cpi%20%5Ccdot%2010%5E%7B-7%7D%20Tm%2FA)
is the vacuum permeability
I is the current in the wire
r is the radial distance from the wire at which the field is calculated
The current in the axon is
![I=0.040 \mu A=0.040 \cdot 10^{-6} A](https://tex.z-dn.net/?f=I%3D0.040%20%5Cmu%20A%3D0.040%20%5Ccdot%2010%5E%7B-6%7D%20A)
,
therefore the magnetic field strength at distance
from the axon is
Answer:
Efficiency = 75%
M.A = 1500
Explanation:
Efficiency is given by the formula;
E = (work output/work input) × 100%
Work output = 500 × 1.5 = 750 J
We are given the work input as 1000 J.
Thus;
Efficiency = (750/1000) × 100% = 75%
Now, to find the mechanical advantage;
Efficiency = (M.A/V.R) × 100
75 = (M.A/5) × 100
M.A = 100 × 75/5
M.A = 1500
Answer:
rotation
Explanation:
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Mantle I think idrk cuz of erosion