Gene expression
Plz choose me for Brainest answer
Nacl = (. 23+35. 5)
= 58.5g
.
1 mol of Nacl = 58.5g
X mol Of Nacl = 25g
X Mol of Na Cl =25 ÷ 58.5
X mol of Nacl = 0.4 mol
Answer:
Explanation:
Here's where all that equation balancing is going to come into use. Since the main object of the question is not the equation, I'm just going to balance it and use it.
4Fe + 3O2 ====> 2Fe2O3
Step One
Find the number of mols of O2 in 24.9 grams of O2
1 mol O2 = 2*16 = 32 grams
x mol O2 = 24.9 grams Cross multiply
32x = 24.9 * 1 Divide by 32
x = 24.9/32
x = 0.778 moles of O2
Step Two
Type the findings under the balanced equations parts. Solve for the number of moles of Fe
4Fe + 3O2 ====> 2Fe2O3
x 0.778
Step Three
Set up the proportion
4/x = 3/0.778 Cross multiply
Step Four
Solve the proportion moles of Fe
4*0.778 = 3x
3.112 = 3x Divide by 3
3.112/3 = 3x/3
x = 1.037 moles of Fe
Step Five
Find the mass of Fe
1 mol Fe = 56 grams
1.037 mol Fe = x Cross Multiply
x = 56*1.037
x = 58.1 grams
Answer:
97.9 g/mol
Explanation:
<em>There is some info missing. I think this is the original question.</em>
<em>An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. He then titrates this solution with 0.0600 M NaOH solutions. When the titration reaches the equivalence point, the chemist finds he has added 95.9 mL of NaOH solution.
</em>
<em>
Calculate the molar mass of the unknown acid.</em>
Let's consider the neutralization between a generic triprotic acid and NaOH.
H₃X + 3 NaOH → Na₃X + 3 H₂O
The moles of NaOH that reacted are:
0.0600 mol/L × 0.0959 L = 0.00575 mol
The molar ratio of NaOH to H₃X is 3:1. The moles of H₃X are 1/3 × 0.00575 mol = 0.00192 mol.
The molar mass of the acid is:
0.188 g / 0.00192 mol = 97.9 g/mol
