<u>Answer:</u> The change in enthalpy for the given system is -642.8 kJ/mol
<u>Explanation:</u>
To calculate the change in enthalpy for given Gibbs free energy, we use the equation:

where,
= Gibbs free energy = -717.5 kJ/mol = -717500 J/mol (Conversion factor: 1 kJ = 1000 J)
= change in enthalpy = ?
T = temperature = 337 K
= change in entropy = 221.7 J/mol.K
Putting values in above equation, we get:

Hence, the change in enthalpy for the given system is -642.8 kJ/mol
Explanation:
Correct option is
D
3
The unbalanced chemical reaction is Al(s)+O
2
(g)→Al
2
O
3
(s)
Balance Al atoms by adding 2 to Al on LHS
2Al(s)+O
2
(g)→Al
2
O
3
(s)
Balance O atoms by adding
2
3
to O
2
on LHS
2Al(s)+
2
3
O
2
(g)→Al
2
O
3
(s)
Multiply the whole equation with 2.
4Al(s)+3O
2
(g)→2Al
2
O
3
(s)
This is the balanced chemical equation. The coefficient of O
2
is 3.
The image of the structure is attached in the image below.
<u>Answer: </u>The correct option is a.) 4-methyl-3-phenyl-3-pentenoic acid
<u>Explanation:</u>
Carboxylic acids are a type of functional group in organic chemistry that have the symbol '-COOH'. A suffix used for this functional group is '-oic acid'.
To name a compound, first look for the longest possible carbon chain.
As in the image attached below, the longest carbon chain has 5 carbon atoms. Thus, the prefix used will be 'pent-'
Also, a methyl substituent is present at the 4th position, a phenyl substituent is located at the 3rd position.
A double bond is also present at the 3rd position and a suffix '-ene' is used.
Hence, the IUPAC name for the given compound is 4-methyl-3-phenyl-3-pentenoic acid.
A=79, N=44 lmk if I’m wrong ?