If U-235 decays into Cs-135 and 4 neutrons, the other nuclide that will be produced is Rb-96 (option D).
<h3>What is radioactive decay?</h3>
A radioactive decay is the process by which an unstable large nuclei emit subatomic particles and disintegrate into one or more smaller nuclei.
According to this question, a radioactive material Uranium- 235 undergoes radioactive decay into Cs- 135 and 4 neutrons (1/0n).
This means that the mass of the products we have is 135 + 4 = 139.
The mass of the nuclide left must be 235 - 139 = 96, hence, the other nuclide that will be produced is Rb-96.
Learn more about radioactive decay at: brainly.com/question/1770619
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The correct option is B.
Mendeleev was the one who originated the idea of arranging elements in the periodic table according to their chemical and physical properties. He left spaces in the periodic table and predicted the discovery of those elements that had not been discovered then. One of these elements is Gallium. He predicted that gallium is going to be a metal and he gave the properties that the element will possess. He also predicted that the element gallium will be placed under aluminium in the periodic table.
Missing table!! write the elements with the first letter of the symbol with Upper Caps letters!!!
http://www.chemeddl.org/services/moodle/media/QBank/GenChem/Tables/EStandardTable.htm
<span>Ni2+ +Pb(s) → Ni(s) + Pb2+
</span>The potential of the oxidation of Pb(s) --> Pb2+(aq) is 0.126 V
The potential of the reduction go Ni2+(aq) --> Ni(s) is -0.25 V
<span>Add the two together and the potential for the reaction is -0.124 V (NO SPONTANEOUS THE SIGN IS NEGATIVE)
</span><span>au3+ + al(s) → au(s) + al3+Au3+(aq) -> Au(s) +1.5 VAl -> Al3+ +1.66VV= 3.16 (SPONTANEOUS THE SIGN OF THE PONTENTIAL IS POSITIVE)</span><span>Sr2+ + Sn(s) → Sr(s) + Sn2+
</span>
Sr2+(aq) + 2 e– <span> Sr(s) V= -2.89V
</span>Sn -> Sn2+ V= 0.14 V
V= -2.75 V (no spontaneous)
<span>Fe2+ + Cu(s) → Fe(s) + Cu2+
</span>Fe2+(aq) + 2 e–<span> </span><span> Fe(s) V= -0.44 V
</span>Cu -> C2+ V = - 0.337V
V= - 0.777V (no spontaneous)
The volume is 2.23 liters of hydrogen gas.
<u>Explanation</u>:
moles of C = grams / molecular mass of C
= 1.04 g / 12.011 g/mol.
= 0.086
The ratio between C and H2 is 1 : 1
moles H2 = 0.086
V = nRT / p
= 0.086 x 0.08206 x 316 K / 1.0 atm
V = 2.23 L.
