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Nata [24]
3 years ago
10

If you are looking for a material that is a good conductor, you will look for a material that will (2 points)

Physics
2 answers:
Nataly_w [17]3 years ago
7 0
B)<span>Readily accept electron flow.</span>
bulgar [2K]3 years ago
4 0

The correct answer to the question is C) Readily accept electron flow.

EXPLANATION:

As per the question, the material given is a good conductor.

A conductor is defined as a conducting substance whose free electron concentration is more in its conduction band. The valence band of the conductor is completely full, and there is a little bit of forbidden energy gap between valence band and conduction band. In a good conductor, both the bands are overlapped.

Due to this electronic arrangement, the conductor has low resistivity and high conductivity. Hence, it will provide a low resistive path to the flow of electrons.

Hence, the correct answer to the question is that a good conductor readily accept electron flow.

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When is thermal equilibrium achieved between two objects?
ki77a [65]
Thermal equilibrium is when a hot and cold object (could also be air) come in contact with each other and over time become the same temperature.
thermal equilibrium is reached when both objects are the same temperature.
4 0
3 years ago
Read 2 more answers
How do I solve for time if I have initial velocity and final speed?
xeze [42]
Final speed = initial speed + (acceleration x time)

(final speed - initial speed) = acceleration x time

Time = (final speed - initial speed) / acceleration
4 0
3 years ago
The graphs display velocity data Velocity is on the y-axis (m/s), while time is on the x-axis (s). Based on the graphs, which da
RUDIKE [14]

Answer:

The first graph is showing the constant acceleration (1 m/s)

Explanation:

The second graph showing the flexible velocity therefore a in the graph is different at t1, t2, t3, t4

The last graph is showing constant velocity therefore there is no acceleration (a = 0)

5 0
3 years ago
Read 2 more answers
Please help ASAP!!
inessss [21]

Answer:

at t=46/22, x=24 699/1210 ≈ 24.56m

Explanation:

The general equation for location is:

x(t) = x₀ + v₀·t + 1/2 a·t²

Where:

x(t) is the location at time t. Let's say this is the height above the base of the cliff.

x₀ is the starting position. At the base of the cliff we'll take x₀=0 and at the top x₀=46.0

v₀ is the initial velocity. For the ball it is 0, for the stone it is 22.0.

a is the standard gravity. In this example it is pointed downwards at -9.8 m/s².

Now that we have this formula, we have to write it two times, once for the ball and once for the stone, and then figure out for which t they are equal, which is the point of collision.

Ball: x(t) = 46.0 + 0 - 1/2*9.8 t²

Stone: x(t) = 0 + 22·t - 1/2*9.8 t²

Since both objects are subject to the same gravity, the 1/2 a·t² term cancels out on both side, and what we're left with is actually quite a simple equation:

46 = 22·t

so t = 46/22 ≈ 2.09

Put this t back into either original (i.e., with the quadratic term) equation and get:

x(46/22) = 46 - 1/2 * 9.806 * (46/22)² ≈ 24.56 m

4 0
3 years ago
A machine, modeled as a simple spring-mass system, oscillates in simple harmonic motion. Its acceleration is measured to have an
ANTONII [103]

a=5000\dfrac{mm}{s}=5\dfrac{m}{s}

f=10{Hz}\Longrightarrow t=\dfrac{1}{10}s

a_{max}=\dfrac{50\frac{m}{s}}{\frac{s}{10}}\cdot\dfrac{1}{\sqrt{2}}=\dfrac{50\dfrac{m}{s^2}}{\sqrt{2}}\approx\boxed{35.4\dfrac{m}{s^2}}

Hope this helps.

r3t40

5 0
3 years ago
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