Impulse = Force * times and also Impulse = change in momentum.
Given that the mass does not change, change if momentum = mass * (final velocity - initial velocity)
Given that you know mass and initial velocity (which is the velicity before the cart hits the wall) you need the final velocity (which is the velocity after the cart hits the wall).
Answer: the velocity of the cart after it hits the wall.
The electric flux through the hole is
.
- Electric flux is the number of electric field lines cutting through the surface and is measured as surface intregal of electric field over that surface
- Mathematically it is given by
where E is the electric field and A is the area. - Gauss's law states that electric flux through closed surface is equal to the 1 / ε₀ times the charge enclosed by that surface which is given by Ф = q / ε₀ where q is the central charge and ε₀ is the permittivity of the medium.
It is given , hollow sphere of radius 10.0cm surrounds a 10.0-μC charge.
The whole surface of hollow sphere 

Area of the hole ( both side ) 

According to Gauss's theorem, the flow from a particular charge in the center is given by

This flux flows through the surface of the sphere, so the flux per unit area which is given by

Flux through area of hole is given by :

Learn about more electric flux here :
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Answer: momentum = 6kgm/s
Explanation:
given that the baseball pitcher is at stationary position, his velocity will be equal to zero. If velocity is zero, his linear momentum will therefore equal to zero.
Linear momentum is the product of mass and velocity. Given that the baseball has
Mass M = 0.15 kg
Velocity V = 40 m/s
Momentum = MV
Momentum = 0.15 × 40 = 6 kgm/s
Answer:
The velocity of the ball before it hits the ground is 381.2 m/s
Explanation:
Given;
time taken to reach the ground, t = 38.9 s
The height of fall is given by;
h = ¹/₂gt²
h = ¹/₂(9.8)(38.9)²
h = 7414.73 m
The velocity of the ball before it hits the ground is given as;
v² = u² + 2gh
where;
u is the initial velocity of the on the root = 0
v is the final velocity of the ball before it hits the ground
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 7414.73 )
v = 381.2 m/s
Therefore, the velocity of the ball before it hits the ground is 381.2 m/s
Answer:
<u>Point </u><u>A</u>
Explanation:
And the strongest force of gravity is point C