It is 5 kg I did this it is right
Answer:
The voltage across the capacitor decreases by a factor of 2
Explanation:
When we put a dielectric material on a capacitor, we generate a polarization on it that changes the capacitance of the capacitor. The dielectric constant is the ratio between the initial capacitance (Co) without the dielectric and the new capacitance (C) with the dielectric:
So, if k is equal to 2:
So, the capacitance is doubled with the dielectric
Because the battery is disconnected, the charge on the plates of capacitor must be constant because conservation of charge.
The effective electric field of a capacitor is the electric filed when we put a dielectric on it, and it is:
With E the initial electric field, so the electric field is halved
Finally, because we know electric field and voltage (V) on a parallel capacitor with distance between plates (d) are related by:
Because electric field and voltage are directly proportional and d remains constant if Electric field is halved, then voltage is halved too. The voltage across the capacitor decreases by a factor of 2.
Answer:
Static friction, F=2.9988 N
Explanation:
Static Friction: It is the friction between two or more solid body that are not moving relative to each other.
When an external force is applied to a body that is in contact with another body, static friction opposes the applied force upto a certain limit, keeping the body at rest. When the applied force exceeds the certain limit the body begins to move. At that moment applied force is equal to limiting value of static friction F.
It varies linearly with normal force(N)
F∝N
F=μN (where μ is constant of proportionality and known as coefficient of static friction)
Now,
Mass, m=1.53 kg
Coefficient of static friction, μ=0.2
Normal force, N=m×g
= (g=9.8 m/s²)
=14.994 N
Static friction, F= μN
=
= 2.9988 N
D. I believe. I havent done the metric system in a while.