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docker41 [41]
3 years ago
5

The three sides of a triangle are n, 4n−8, and 2n+8. If the perimeter of the triangle is 63 feet, what is the length of each sid

e?
Mathematics
1 answer:
svlad2 [7]3 years ago
8 0

Answer:

  9 ft, 28 ft, 26 ft

Step-by-step explanation:

The perimeter is the sum of side lengths, so ...

  P = a + b + c

  63 = n +(4n -8) +(2n +8) . . . . fill in the given side lengths

  63 = 7n . . . . . . simplify

  9 = n . . . . . . . . divide by 7

  4n -8 = 36 -8 = 28 . . . . second side length

  2n +8 = 18 +8 = 26 . . . . third side length

The side lengths are 9 ft, 28 ft, 26 ft..

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Calculus graph please help
tresset_1 [31]

Answer:

See Below.

Step-by-step explanation:

We are given the graph of <em>y</em> = f'(x) and we want to determine the characteristics of f(x).

Part A)

<em>f</em> is increasing whenever <em>f'</em> is positive and decreasing whenever <em>f'</em> is negative.

Hence, <em>f</em> is increasing for the interval:

(-\infty, -2) \cup (-1, 1)\cup (3, \infty)

And <em>f</em> is decreasing for the interval:

\displaystyle (-2, -1) \cup (1, 3)

Part B)

<em>f</em> has a relative maximum at <em>x</em> = <em>c</em> if <em>f'</em> turns from positive to negative at <em>c</em> and a relative minimum if <em>f'</em> turns from negative to positive to negative at <em>c</em>.

<em>f'</em> turns from positive to negative at <em>x</em> = -2 and <em>x</em> = 1.

And <em>f'</em> turns from negative to positive at <em>x</em> = -1 and <em>x</em> = 3.

Hence, <em>f</em> has relative maximums at <em>x</em> = -2 and <em>x</em> = 1, and relative minimums at <em>x</em> = -1 and <em>x</em> = 3.

Part C)

<em>f</em> is concave up whenever <em>f''</em> is positive and concave down whenever <em>f''</em> is negative.

In other words, <em>f</em> is concave up whenever <em>f'</em> is increasing and concave down whenever <em>f'</em> is decreasing.

Hence, <em>f</em> is concave up for the interval (rounded to the nearest tenths):

\displaystyle (-1.5 , 0) \cup (2.2, \infty)

And concave down for the interval:

\displaystyle (-\infty, -1.5) \cup (0, 2.2)

Part D)

Points of inflections are where the concavity changes: that is, <em>f''</em> changes from either positive to negative or negative to positive.

In other words, <em>f </em>has an inflection point wherever <em>f'</em> has an extremum point.

<em>f'</em> has extrema at (approximately) <em>x</em> = -1.5, 0, and 2.2.

Hence, <em>f</em> has inflection points at <em>x</em> = -1.5, 0, and 2.2.

7 0
2 years ago
Evaluate 0.3y + y/x when y = 10 and z =5
coldgirl [10]

Answer:

5

Step-by-step explanation:

0.3*10=3

10/5=2

--------------------

3+2=5

8 0
3 years ago
Y= what ? Need help ASAP
lana66690 [7]
The equation is asking for you to write out an equation y= x + b. The equation should be y= 2x - 1
3 0
3 years ago
Read 2 more answers
Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e
Sedaia [141]

The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let \%R_{A} be the quantity of nonzero elements in R_{A}.

Let C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right).

Parity demands that \%R_{A} and\%R_{B} must equal 2 or 4.

Case 1: \%R_{A}=4 and \%R_B=4. There are \left(\begin{array}{l}3\\ 2\end{array}\right)=3 ways to put 2-1's in R_A, so there are 3 ways.

Case 2: \%R_{A}=2 and \%R_B=4. There are 3 ways to position the -1 in R_A, 2 ways to put the remaining -1 in R_B (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of \%R_{A}=4,\%R_{B}=2 for a complete of 24 ways.

Case 3: \%R_A=\%R_B=2. There are 3 ways to put the -1 in R_{A}. Now, there are two cases on what happens next.

  • The 1 in R_B goes directly under the -1 inR_A. There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in R_C andR_D. (Either the 1 comes first inR_C or the 1 comes first in R_D.)
  • The 1 in R_B doesn't go directly under the -1 in R_A. There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

#SPJ4

3 0
2 years ago
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PLS HLP LOTS OF POINTS
cupoosta [38]
380

3 hundreds  8 tens
2 hundreds 18 tens
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2 years ago
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