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docker41 [41]
3 years ago
5

The three sides of a triangle are n, 4n−8, and 2n+8. If the perimeter of the triangle is 63 feet, what is the length of each sid

e?
Mathematics
1 answer:
svlad2 [7]3 years ago
8 0

Answer:

  9 ft, 28 ft, 26 ft

Step-by-step explanation:

The perimeter is the sum of side lengths, so ...

  P = a + b + c

  63 = n +(4n -8) +(2n +8) . . . . fill in the given side lengths

  63 = 7n . . . . . . simplify

  9 = n . . . . . . . . divide by 7

  4n -8 = 36 -8 = 28 . . . . second side length

  2n +8 = 18 +8 = 26 . . . . third side length

The side lengths are 9 ft, 28 ft, 26 ft..

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Answer:

Height(h) = 24in

Area = 204in²

Step-by-step explanation:

we would use the heron formula because we have all the sides to calulate the area

S  = (A+B+C)/2 = (25 + 17 + 26)/2 = 68/2 = 34

area = √s(s-a)(s-b)(s-c)  = √34(34-25)(34-17)(34-26) = √34(9)(17)(8) = √34x9x17x8 = √41616 = 204

area= (1/2)bh

    204 = (1/2)bh b= 17, h =?

204 = (1/2)17h

204 x 2 = 17h

408 = 17h

h = 408/17 = 24in

Height(h) = 24in

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