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Talja [164]
4 years ago
9

1.

Physics
1 answer:
8_murik_8 [283]4 years ago
5 0

Answer: 2.61 s

Explanation:

We are given the following data:

s=5 ft is the initial height of the object

v=40 ft/s is the initial height of the object

In addition, the motion of the object is given by:

h=-16t^{2}+ vt +s (1)

Where:

h=0 ft is the final height of the object

t is the time the object is in the air before hitting the ground

Rewritting (1) with the given data:

0=-16t^{2}+ 40t +5 (2)

Solving the quadratic equation with the quadratic formula t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}, where a=-16, b=40, c=5 and choosing the positive value of time:

t=\frac{-40\pm\sqrt{(-40)^{2}-4(-16)(5)}}{2(-16)} (3)

t=2.61 s (4) This is the time

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