The first one is C. Hope this helps!! If you need anymore help just message me and I will try to get back to you quickly and help in any way i can!
Answer:
v = 10.1 m/s
Explanation:
As we know that by the law of conservation of volume the rate of volume flowing through the pipe will remain conserved
so here we have flow rate given as
now we have
now we have
now from above equation we have
Finding out the acceleration 12/3 = 4m/s^2
thus it is descending so the actual acceleration would be 9.8-4 = 5.8 m/s^2
the weight will be 90*5.8 = 522 N
522/9.8 = 53.2 kg
The more it is Red shifted.
Answer:
Temperature of parcel at 1000 ft is 85.5°F
Explanation:
Temperature of parcel at 0 ft =T₁ = 91.0°F
Dry adiabatic rate = 5.5°F/100 ft
Temperature of parcel at H₂ (1000 ft) = T₂ =?
Height of LCL = 5000 ft
As (1000<5000), so using the formula for parcel below or at the LCL i.e.