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german
4 years ago
10

Laboratory equipment is cleaned and properly stored after use primarily so that -- chemical products can be measured and recorde

d as data chemical products can be measured and recorded as data time is saved in setting up the next experiment time is saved in setting up the next experiment toxic materials can be kept in the laboratory toxic materials can be kept in the laboratory the possibility of contamination in the laboratory is minimized
Chemistry
1 answer:
agasfer [191]4 years ago
3 0

Answer:

the possibility of contamination in the laboratory is minimized

Explanation:

When a particular laboratory equipment is used for a given purpose, it can not be used four another purpose until it has been thoroughly washed. This is done in order to avoid contamination when the equipment is subsequently used for a different purpose.

Hence, if a laboratory equipment is not properly cleaned and stored after use, they remain contaminated and give inaccurate results when subsequently used.

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A piece of high-density Styrofoam measuring 24.0 cm by 36.0 cm by 5.0 cm floats when placed in a tub of water. When a 1.5 kg boo
zheka24 [161]

Explanation:

The given data is as follows.

         Width of Styrofoam = 24.0 cm

          Length of Styrofoam = 36.0 cm

          Height of Styrofoam = 5.0 cm

Therefore, volume of the Styrofoam will be calculated as follows.

                  Volume = length × width × height

                                =  (36.0 × 24.0 × 5.0) cm^{3}

                                 = 4320 cm^{3}

or,                             = 4.32 \times 10^{3} cm^{3}

As Styrofoam partially sinks at 3.0 cm and total height of Styrofoam is 5.0 cm. Hence, height of Styrofoam above the water is (5.0 - 3 cm) = 2 cm.

So, volume of water displaced is as follows.

          24.0 cm × 36.0 cm × 2.0 cm

         = 1.73 \times 10^{3} cm^{3}

Hence, mass of displaced water is as follows.

                 mass = density × volume

                           = 1.00 g/cm^{3} \times 1.73 \times 10^{3} cm^{3}

                           = 1.73 \times 10^{3} g

Since, book is placed on the Styrofoam. Therefore, mass of water displaced is also equal to the following.

             Mass of water displaced = mass of book + mass of Styrofoam

                  1.73 \times 10^{3} g = 1500 g + mass of Styrofoam

                   (1730 - 1500) g = mass of Styrofoam

                   mass of Styrofoam = 230 g

Therefore, calculate the density of Styrofoam as follows.

                   Density = \frac{mass}{volume}  

                                 = \frac{230}{4.32 \times 10^{3} cm^{3}}

                                 = 53.24 \times 10^{-3} g cm^{-3}

Thus, we can conclude that the density of Styrofoam is 53.24 \times 10^{-3} g cm^{-3}.

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3 years ago
What is a polar liquid?
BabaBlast [244]
Polar liquids have both negative and positive ends.
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What is the ratio of hydrogen atoms to sulfur atoms in sulfuric acid, h2so4?
Vsevolod [243]
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4 years ago
How many molecules are in 9.8 grams of calcium
solniwko [45]
Molar mass of Calcium ( Ca ) = 40.078 g/mol

Number of moles in 9.8 grams :

1 mole Ca -----------> 40.078 g
mole Ca -------------> 9.8 g

moles Ca = 9.8 / 40.078

moles Ca = 0.2445 moles

number of molecules:

1 mole ----------------> 6.02x10²³ molecules
0.2445 moles --------> ?

= 0.2445 * 6.02x10²³

= 1.47x10²³ molecules

hope this helps!.

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