Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 239 mL .
2 answers:
Answer:
The mass of the piece of aluminum is 645 g.
Explanation:
Density is given by the relationship between mass and volume:
ρ =
If we take de volume V and pass to multiply the density ρ, we have:
m = ρ * V (Equation 1)
with this formula we can find the mass.
We have that ρ = 2.70 and V = 239mL
So, replacing these values in Equation 1, we can find the value for the mass:
m = 2.70 * 239mL
m = 645 g
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Answer:
El potencial celular estándar, is +0.46 V
Explanation:
Las reacciones de media célula son;
Media reacción del ánodo Cu²⁺ + 2e⁻ ↔ Cu, E ° = 0.34 V
Media reacción catódica 2Ag + 2e⁻ ⁻ 2Ag, E ° = 0.80 V
Sin embargo tenemos para hierro Fe²⁺ + 2e⁻ ↔ Fe, E ° -0.44 V
y Fe³⁺ + e⁻ ↔ Fe²⁺, E ° = 0.77 V
que es más alta que la del cobre presente, por lo tanto, el cobre se oxidará en el ánodo
Por lo tanto, en el ánodo, tendremos
Cu → Cu²⁺ + 2e⁻ (E ° = -0.34 V)
En el cátodo
2Ag + 2e⁻ → 2Ag (E ° = 0.80 V)
El potencial celular estándar, = +0.46 V