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Aloiza [94]
3 years ago
13

interval (from lowering the body to his feet taking off) lasts for 0.3 s and the mass of the player is 90 kg. Ignore air resista

nce. Part A Determine the force that the the player exerts on the surface when he jumps. Express your answer to one significant figure and include the appropriate units. Enter positive value if the force is upward and negative value if the force is downward.
Physics
1 answer:
steposvetlana [31]3 years ago
8 0

Answer:

The force applied to the surface is 9 kilo Newton.

Explanation:

While jumping on the surface the player applies the force that is equal to its weight on the surface.

The mass of the player is given as 90 kg.

Force applied by the player = weight of the player

Force applied by the player = m × g

Where m is the mass of the player and g is acceleration due to gravity

Force applied by the player = 90 × 9.8

Force applied by the player = 882 Newton

Expressing your answer to one significant figure, we get

Force applied by the player =0. 9 kilo Newton

The force applied to the surface is 0.9 kilo Newton.

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You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 x
Blizzard [7]

Complete Question

You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 * 10^{-3} meters apart. However, by placing a piece of crystal in one of the slits, you are able to make it so that the rays of light that travel through the two slits are Ï out of phase with each other (that is to say, Ao,- ). If you observe that on a screen placed 4 meters from the two slits that the distance between the bright spot closest to center of the pattern is 1.5 cm, what is the wavelength of the laser?

Answer:

The  wavelength is  \lambda  =  56250 nm

Explanation:

From the question we are told that

   The  distance of slit separation is  d =  7.5 *10^{-3} \  m

   The  distance of the screen is  D =  4 \  m

    The  distance between the bright spot closest to the center of the interference  is  k   = 1.5 \ cm = 0.015 \  m

   

Generally the width of the central  maximum fringe produced is mathematically represented as

        y  =  2 *  k  = \frac{ D  *  \lambda}{d}

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7 0
3 years ago
……………………………………………………………..?
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Answer:

C

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Wattage = 48 watts.

Now you need to use the power formula

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Work = 48 * 180

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2 years ago
Consider two sizes of disk, both of mass M. One size of disk has radius R; the other has radius 4R. System A consists of two of
Harman [31]

Answer:

4 smaller disks

Explanation:

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4MR² = MR²(2 + n/2)

MR² will cancel out to give;

4 = 2 + n/2

Multiply through by 2 to give;

8 = 4 + n

n = 8 - 4

n = 4

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