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goblinko [34]
3 years ago
15

A block of aluminum with a volume of 10 cm3 is placed in a beaker of water filled to the brim. Water overflows. The same is done

in another beaker with a 10 cm3 block of lead. Does the lead block displace more, less, or the same amount of water?
a. Both blocks displace the same amount of water.
b. The lead block will displace less water.
c. The lead block will displace more water.
Physics
1 answer:
mihalych1998 [28]3 years ago
7 0

Answer:

a) Both blocks displace the same amount of water.

Explanation:

Specific gravity (S.G.) is a quantity that tells how much and object is submerged on water and is given by:

S.G=\frac{\rho_{block}}{\rho_{fluid}}

with ρ the densities

Density of water is 997 \frac{kg}{m^{3}} and density of aluminum is 2712 \frac{kg}{m^{3}}

So:

S.G=\frac{2712}{997}=2.72

A S.G. value bigger than one means the object is totally submerged so the water displaced is equal to the volume of the cube.

For the lead (density = 11340\frac{kg}{m^{3}}) block we're going to calculate specific gravity in this case:

S.G=\frac{11340}{997}=11.37

Again S.G gravity is bigger than 1, so the lead block is totally submerged too, that implies the volume of water displaced is the volume of the block, that is the same volume as the aluminum block, so a is the correct one.

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a)

Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.

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The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....

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