1(km)cubed = (1,000 m) x (1,000 m) x (1,000 m) = 1 billion cubic meters
1.4 x 10 to the 9 cubic km = 1.4 x 10 to the 9 x (10 to the 9 cubic meters) =
1.4 x 10 to the 18 cubic meters.
The ship's average speed during the 12 seconds is
(1/2) (58 + 153)
= (1/2) (211 m/s)
= 105.5 m/s .
Traveling for 12 seconds at an average speed of 105.5 m/s ,
the ship covers
(12 sec) x (105.5 m/s)
= 1,266 meters during the acceleration
Answer:
a = = 37.2V
b = 13.39MJ
Explanation:
Given that
L = 170 × 10³
r = d/2
= 10cm / 2 = 5 cm
current I = 100A
we are to find the potential drop across the cable
so, we can use ohm’s law
V = IR = I (ρL/A)
ρ = resistivity of the copper
= 1.72 × 10⁻⁸ Ω.m
A = πr²
V = I(ρL/πr²)
= 100 (( 1.72 × 10⁻⁸ * 170 × 10³) / ( π * 0.05²))
= 37.2V
(b)
Energy (loss) = Pt
Enery (loss) = IVt
3600s per hour
= (100A)(37.2V)(3600s)
= 13.39MJ
Answer:
ω=6684.51 rpm
Explanation:
r= 30cm= 0.3m
a= 15000gs (convert to m/s^{2}
1g = 9.8 m/s^{2}
a= 15000 *9.8 = 147000 m/s^{2}
a=\frac{v^{2} }{r}
147000 = \frac{v^{2} }{0.3}
147000*0.3 = v^{2}
44100 = v^{2}
√44100 = v
210m/s = v
v=210m/s (linear velocity)
we will convert this to angular velocity
ω=\frac{v}{r}
ω= 210/0.3
ω= 700 rads^{-1}
we will convert this to rev per minute
1rad per second = 9.5493 rev per minute
ω= 700*9.5493
ω=6684.51 rpm
A) 350 J
- The initial internal energy of the cup is
- The final internal energy of the cup is
According to the first law of thermodynamics:
where
Q is the heat absorbed by the system
W is the work done on the system
The work done on the system in this case is 0, so we can rewrite the equation as
And so we find the heat transferred
B) IN the cup
Explanation:
in this situation, we see that the internal energy of the cup increases. The internal energy of an object/substance is proportional to its temperature, so it is a measure of the average kinetic energy of the molecules of the object/substance. Therefore, in this case, the temperature (and the energy of the molecules of the substance) has increased: this means that heat has been transferred INTO the system from the environment (the heat came from the sun).
