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2 years ago

How does the Earth release energy back into the atmosphere?

1 answer:

8 0

In general, the Earth releases energy back to the atmosphere through reflection, evaporation, and radiation. The Earth gets energy from the sunlight, part of which it absorbs, while part it reflects backwards, thus giving energy to the atmosphere. Also, the heating up of the Earth by the absorbed sunlight, radiates back in the lower layers of the atmosphere, again giving back energy to it. The water vapor is another way in which the Earth gives back energy tot he atmosphere as through the evaporation, the water vapor gets into the lower parts of the atmosphere and gives energy to it.

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Which object will sink in freshwater, which has a density of 1.0 g/cm3?

Pani-rosa [81]

Answer:

Object 2, which has a density of 1.9 g/cm3, since it has more density than freshwater.

6 0

2 years ago

Read 2 more answers

A certain heat engine takes in 300 J of energy from a hot source and then transfers 200 J of that energy to a colder object. Wha

Greeley [361]

Answer:

The efficiency is 0.33, or 33%.

Explanation:

From the thermodynamics equations, we know that the formula for the efficiency of a heat engine is:

$\eta=1-\frac{Q_2}{Q_1}$

Where η is the efficiency of the engine, Q_1 is the heat energy taken from the hot source and Q_2 is the heat energy given to the cold object. So, plugging the given values in the formula, we obtain:

$\eta=1-\frac{200J}{300J}=0.33$

This means that the efficiency of the heat engine is 0.33, or 33% (The efficiency of an engine is dimensionless).

5 0

2 years ago

A 0.75 kg book is pushed across the table with an acceleration of 0.3 m/s2. What force is being applied to the

Brums [2.3K]

Answer:

$\boxed {\boxed {\sf 0.225 \ Newtons}}$

Explanation:

We are asked to find the force being applied to a book. According to Newton's Second Law of Motion, force is the product of mass and acceleration.

$F= ma$

The mass of the book is 0.75 kilograms and the acceleration is 0.3 meters per square second. Substitute these values into the formula.

m= 0.75 kg
a= 0.3 m/s²

$F= 0.75 \ kg * 0.3 \ m/s^2$

Multiply.

$F =0.225 \ kg * m/s^2$

1 kilogram meter per second squared is equal to 1 Newton. Therefore, our answer of 0.225 kilogram meters per second squared is equal to 0.225 Newtons.

$F= 0.225 \ N$

<u>0.225 Newtons of force</u> are applied to the book.

5 0

2 years ago

what does the presence of the mosesaurus fossils tell the initial location and positioning of soyth america africa and antartica

kicyunya [14]

The remains of Mesosaurus- a crocodile-like reptilian tells United States that South America, Africa and Antarctica were once joined along which implies they were once an enormous continent. However, because of the idea called the geological phenomenon, this one massive continent began to break so making individual continents.

3 0

2 years ago

If it requires 2.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re

valina [46]

Answer:

16 J

Explanation:

It is given that,

Work done, W = 2 J

A spring is stretched by 2.0 cm from its equilibrium length

We need to find how much more work will be required to stretch it an additional 4.0 cm.

Let k is the spring constant of the spring. When W = 2J, and x = 2 cm, then energy required to stretch the spring is :

$U=\dfrac{1}{2}kx^2\\\\k=\dfrac{2U}{x^2}\\\\k=\dfrac{2(2)}{(0.02)^2}\\\\k=10000\ N/m$

The energy required to stretch the spring from 2 cm to additional 4 cm i.e. 2+4= 6 cm.

$W=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 10000\times ((0.06)^2-(0.02)^2)\\\\W=16\ J$

So, the required work done is 16 J.

7 0

2 years ago