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saveliy_v [14]
3 years ago
10

How does the Earth release energy back into the atmosphere?

Physics
1 answer:
JulsSmile [24]3 years ago
8 0

In general, the Earth releases energy back to the atmosphere through reflection, evaporation, and radiation. The Earth gets energy from the sunlight, part of which it absorbs, while part it reflects backwards, thus giving energy to the atmosphere. Also, the heating up of the Earth by the absorbed sunlight, radiates back in the lower layers of the atmosphere, again giving back energy to it. The water vapor is another way in which the Earth gives back energy tot he atmosphere as through the evaporation, the water vapor gets into the lower parts of the atmosphere and gives energy to it.

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If you measure a change in temperature, then the _____.
kherson [118]

Answer:

C. total heat energy of the substance has increased

Explanation:

This is because when there is a change in temperature, the heat energy of a substance either increases or decreases. If the temperature increases, its heat energy increases and if its temperature decreases, its heat enery decreases.

6 0
4 years ago
YOU GUYS!!!!! I HAVE TO TURN IN A POWERPOINT IN 30 MINUTES! HELP!!!!!! WHEN WAS PLASMA ADDED AS A STATE OF MATTER?!?!?!?!
ruslelena [56]

a plasma is a hot ionized gas consisting of equal numbers and positively charged ions and negativly charged electrons. the characterisitcs of plasma are different from those of oirdinary gases so plama is consideres the fourth state of matter

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3 years ago
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What is heat energy!? ​
nordsb [41]

Answer:

heat, energy that is transferred from one body to another as the result of a difference in temperature. If two bodies at different temperatures are brought together, energy is transferred—i.e., heat flows—from the hotter body to the colder. example: stove

Explanation:

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5 0
3 years ago
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The bright yellow light emitted by a sodium vapor lamp consists of two emission lines at 589.0 and 589.6 nm. What are the freque
stiv31 [10]

Answer:

Explanation:

Given

wavelength of emissions are

\lambda _1=589 nm

\lambda _2=589.6 nm

Energy is given by

E=\frac{hc}{\lambda }

where h=Planck's constant

x=velocity of Light

\lambda=wavelength of emission

E_1=\frac{6.626\times 10^{-34}\times 3\times 10^8}{589\times 10^{-9}}

E_1=3.374\times 10^{-19} J

E_1 in kJ/mol

E_1=203.2 kJ/mol

frequency corresponding to this emission

\nu =\frac{c}{\lambda }

\nu _1=\frac{3\times 10^8}{589\times 10^{-9}}

\nu _1=5.09\times 10^{14} Hz

Energy corresponding to \lambda _2

E_2=\frac{6.626\times 10^{-34}\times 3\times 10^8}{589.6\times 10^{-9}}

E_2=3.371\times 10^{-19} J

E_2=203.02 kJ/mol

frequency corresponding to this emission

\nu =\frac{c}{\lambda }

\nu _1=\frac{3\times 10^8}{589.6\times 10^{-9}}

\nu _1=5.088\times 10^{14} Hz

6 0
3 years ago
A force of 100. newtons is used to move an object a distance of 15 meters with a power of 25 watts. Find the time it takes to do
Flauer [41]
<h3>It takes 60 seconds to do the work</h3>

<em><u>Solution:</u></em>

Given that,

Force = 100 newtons

Distance = 15 meters

Power = 25 watts

To find: time it takes to do the work

<em><u>Find the work done:</u></em>

work = force \times displacement\\\\work = 100\ newtons \times 15\ meters\\\\work = 1500\ joule

<em><u>Find the time taken</u></em>

power = \frac{work}{time}\\\\25\ watts = \frac{1500\ joule}{time}\\\\time = \frac{1500\ joule}{25\ watt}\\\\time = 60\ second

Thus it takes 60 seconds to do the work

3 0
3 years ago
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