Answer:
24,000 m
Explanation:
First find the rocket's final position and velocity during the first phase in the y direction.
Given:
v₀ = 75 sin 53° m/s
t = 25 s
a = 25 sin 53° m/s²
Find: Δy and v
Δy = v₀ t + ½ at²
Δy = (75 sin 53° m/s) (25 s) + ½ (25 sin 53° m/s²) (25 s)²
Δy = 7736.8 m
v = at + v₀
v = (25 sin 53° m/s²) (25 s) + (75 sin 53° m/s)
v = 559.0 m/s
Next, find the final position of the rocket during the second phase (as a projectile).
Given:
v₀ = 559.0 m/s
v = 0 m/s
a = -9.8 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (559.0 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 15945.5 m
The total displacement is:
7736.8 m + 15945.5 m
23682.2 m
Rounded to two significant figures, the maximum altitude reached is 24,000 m.
Displacement is how far something is from its starting position
for example if X moved 10 feet, turned around and moved 30 feet, its distance would be 40, but the displacement would be 20,
and if Y Moved 2 feet, and turned around and moved 22 feet, its distance would be 24, but its displacement would also be 20
Sunspot cycles, solar flares, prominences, layers of the Sun, coronal mass<span> ejections, and </span>nuclear<span> reactions</span>
Answer:we can calculate the answer by following steps;
Explanation:
