The astronaut's weight on the Earth's surface can be determined from
<span>F = m g = 579.2 N subsituting </span><span> mass equal to 59.1 kg and acceleration due to gravity equal to 9.8 m/s². When the variables are mass of the earth and the radius of the earth, </span>F = k m / r². Thus, doubling the mass of the earth would double his weight and doubling the radius would decrease the original weight by 1/4. Hence, <span>579.2 N* 2* 1/4 equal to 290 N. Answer is B.</span>
Answer:
a. 100N +60N =160N
b. . the box will move in the direction the force is applied.
Answer:
<em>Galvanómetro</em>
Explanation:
Un galvanómetro es un dispositivo eléctrico utilizado para <em>detectar la presencia de corriente y voltaje pequeños o para medir su magnitud.</em> Los galvanómetros se utilizan principalmente en puentes y potenciómetros.
Answer:
95.7v
Explanation
Using Faraday's law of electromagnetic induction we know that rate of change in magnetic flux will induce EMF in closed loop
So it is given as
E= Ndစ/dt
E= N BA-0/ deta t
Given that
N = 58turns
B = 1.10T
A = 0.150m^²
Deta t= 0.1s
now we have
E = 58(1.10x0.150)/0.1
= 95.7v
Magnetic flux is decreasing, so the direction of the current will be to aid the decreasing flux $decrease= CLOCKWISE
Explanation:
Answer:
B. Inelastic collision
Explanation:
There are two types of collision:
- Elastic collision: in an elastic collision, both the total momentum of the objects and the total kinetic energy of the objects involved are conserved before and after the collision
- Inelastic collision: in an inelastic collision, the total momentum of the objects is conserved before and after the collision, while the total kinetic energy is not - in fact, some of the kinetic energy is converted into other forms of energy (such as thermal energy) due to the presence of frictional forces
In particular, a perfectly inelastic collision is an inelastic collision in which the two objects stick together after the collision: in such a situation, the amount of kinetic energy "lost" (=converted into other forms) is maximum.
In the situation described in the problem, the two skaters stick together after the collision, so this is an example of perfectly inelastic collision.