The equation is as follows;
2CH3OH(g) = 2CH4(g) + O2(g), ΔH= +252.8 kJ
From the equation; for the reaction to produce 2 moles of methane (32g) an energy of 252.8 kJ is released.
Therefore; for an energy of 82.3 kJ the number of moles that will be produced will be; = (2×82.3)/252.3
= 0.6524 moles
which is equivalent to 0.6524 × 16 = 10.438 g
There, the mass of CH4 produced will be 10.438 g
Answer:
The solutions should be added in this order NaCl > Na2SO4 > Na2S
Explanation:
Silver is insoluble as a chloride, so the silver ions get precipitated on addition of chloride ion as silver chloride. This means Ag+ would be removed the first.
So we will add NaCl in the first step.
The following reaction will occur.
Ag+ + Cl- → AgCl(s)
Both, Pb2 and Ni are soluble as chlorides. (lead chloride is soluble as a hot solution but will ppt when colder).
When we add Na2SO4, Pb2+ will get precipitated (because it's insoluble) as PbSO4 and Ni will remain soluble as NiSO4 is soluble in water.
The reaction that will occur is:
Pb^2+ + SO4^2- → PbSO4(s)
Nickel is insoluble as a sulfide. So when we will add Na2S, nickel will be precipitated as sulfide and be able to separate and be collected.
The solutions should be added in this order NaCl > Na2SO4 > Na2S
Answer: -
Volume of NaOH = 461 mL = 461/1000 = 0.461 L
pH = 10.0
Using the relation pH + pOH = 14.00
pOH = 14.00 - 10.00= 4.00
Using the relation
[OH⁻] = 
= 
M
Since NaOH is a monobasic acid,
[NaOH] = [OH⁻] = M
Amount of NaOH = [NaOH] x Volume of NaOH
= M x 0.461 L
= 4.61 x 10⁻⁵ mol
Molar mass of NaOH = 23 x 1 + 16 x 1 + 1 x1
= 40 g / mol
Mass of NaOH required = 4.61 x 10⁻⁵ mol x 40 g/ mol
= 1.84 x 10⁻³ g
Explanation:
The number acquired by an element after the lose or gain of an electron is called oxidation number.
For example, 
Here, oxidation number of Fe(s) is 0 and Fe in 
is +3.
Oxidation number of O in 
is 0 as it is present in its elemental state.
The oxidation number of O in is calculated as follows.
Hence, oxidation number of O in is -2.
- The loss of electrons by an element or substance is called oxidation. Here, electrons are being lost by Fe(s) as an increase in oxidation state is occurring. So, Fe(s) is oxidized.
- The gain of electrons by an element or substance is called reduction. Here, electrons are being added to
as a decrease in its oxidation state is occurring. So, is reduced.
- An element or compound which is being reduced is called oxidizing agent. Here, is the oxidizing agent.
- An element or compound which is being oxidized is called reducing agent. Here, Fe(s) is the reducing agent.
