Answer:
T=1.566 N.m
Explanation:
Given that:
rotational speed of the scrank shaft, N = 2500 rpm
power produced by one cylinder, P = 410 W
We know, in case of rotational power:

where: T= torque
Substituting the respective values in the above eq.


T=1.566 N.m is the torque applied by the each piston of the engine.
Answer:
400 J
Explanation:
Work is done when a force that is applied to an object moves that object.
The work is calculated by multiplying the force by the amount of movement of an object
W = F * d
here the man has to work against the gravitational field. (against his weight)
F =100 N
Work done = F * d
= 100 * 4
= 400 J
Answer:
The magnitude of the magnetic force acting on the wire is zero, because the magnetic field is parallel to the wire.
In fact, the magnetic force exerted by the magnetic field on the wire is
where I is the current in the wire, L the length of the wire, B the magnetic field intensity and the angle between the direction of B and the wire. In our problem, B and the wire are parallel, so the angle is and so , therefore the magnetic force is zero: F=0.