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levacccp [35]
3 years ago
8

airplane in flight has a pressure difference between the lower and upper wing surface; this provides an upward force that balanc

es the weight of the plane. If a plane has a wing area of 167 m 2 and a fully loaded mass of 77000 kg, what pressure difference is required to keep the plane aloft?
Physics
1 answer:
Dvinal [7]3 years ago
3 0

Answer:

4523.17365 Pa

Explanation:

m = Mass of plane = 77000 kg

F = Force = Weight = mg

g = Acceleration due to gravity = 9.81 m/s²

A = Total area of wings = 167 m²

The pressure difference would be

\Delta P=\dfrac{F}{A}\\\Rightarrow \Delta P=\dfrac{77000\times 9.81}{167}\\\Rightarrow \Delta P=4523.17365\ Pa

The pressure difference required to keep the plane aloft is 4523.17365 Pa

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A moving object is in equilibrium. Which best describes the motion of the object if no forces change?
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Reading Check: (Describe) how pressure changes as the velocity of a fluid<br> increases.
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3 years ago
Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to
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Answer:

P2 = 128,205 pascal.

Explanation:

<u>Given the following data;</u>

Original Pressure, P1 = 100,000 pascals

Original Temperature, T1 = 273K

New Temperature, T2 = 350K

To find new pressure P2, we would use Gay Lussac' law.

<em>Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas. </em>

Mathematically, Gay Lussac's law is given by;

PT = K

Where;

  • P represents pressure.
  • T represents temperature.
  • K is the constant of proportionality.

\frac{P1}{T1} = \frac{P2}{T2}

<em>Making P2 as the subject formula, we have;</em>

P_{2}= \frac{P1}{T1} * T_{2}

Substituting into the equation, we have;

P_{2}= \frac{100000}{273} * 350

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P2 = 128205.13 ≈ 128205 pascal.

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2 years ago
A car travels at an average speed of 60 km / h for 15 minutes. How far does the car travel in 15 minutes?
salantis [7]

Answer:

15km

Explanation:

Given parameters:

Average speed = 60km/hr

Time taken  = 15min

Unknown:

Distance  = ?

Solution:

The distance traveled can de derived using the expression below;

      Distance  = Average speed x time taken

Now let us convert the time to hr;

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              15min = \frac{15}{60}   = 0.25hr

Distance  = 60km/hr x 0.25hr  = 15km

6 0
2 years ago
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