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levacccp [35]
3 years ago
8

airplane in flight has a pressure difference between the lower and upper wing surface; this provides an upward force that balanc

es the weight of the plane. If a plane has a wing area of 167 m 2 and a fully loaded mass of 77000 kg, what pressure difference is required to keep the plane aloft?
Physics
1 answer:
Dvinal [7]3 years ago
3 0

Answer:

4523.17365 Pa

Explanation:

m = Mass of plane = 77000 kg

F = Force = Weight = mg

g = Acceleration due to gravity = 9.81 m/s²

A = Total area of wings = 167 m²

The pressure difference would be

\Delta P=\dfrac{F}{A}\\\Rightarrow \Delta P=\dfrac{77000\times 9.81}{167}\\\Rightarrow \Delta P=4523.17365\ Pa

The pressure difference required to keep the plane aloft is 4523.17365 Pa

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Answer:

a)<em> It took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves. </em>

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Explanation:

The electromagnetic spectrum is the distribution of radiation due to the different frequencies at which it radiates and its different intensitie. That radiation is formed by electromagnetic waves, which are transverse waves formed by an electric field and a magnetic field perpendicular to it.

The distribution of the radiation in the electromagnetic spectrum can also be given in wavelengths, but it is more frequent to work with it at frequencies:

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<em>a) Find the time it took for his voice to reach the Earth via radio waves.</em>

To know the time that took for Neil Armstrong's voice to reach the Earth via radio waves, the following equation can be used:

c = \frac{d}{t}  (1)

Where v is the speed of light, d is the distance and t is the time.

Notice that t can be isolated from equation 1.

t = \frac{d}{c}  (2)

The distance from the Earth to the Moon is 3.85x10^{8} m, therefore.

t = \frac{3.85x10^{8} m}{3x10^{8}m/s}

t = 1.28s

Hence, it took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves.

<em>b) Determine the minimum time that will be required for a message from Mars to reach the Earth via radio waves.</em>

The distance from the Earth to the Mars at its closest approach is 5.76x10^{10}m, therefore.

t = \frac{5.76x10^{10}m}{3x10^{8}m/s}

t = 192s

Hence, the minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds.

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