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levacccp [35]
3 years ago
8

airplane in flight has a pressure difference between the lower and upper wing surface; this provides an upward force that balanc

es the weight of the plane. If a plane has a wing area of 167 m 2 and a fully loaded mass of 77000 kg, what pressure difference is required to keep the plane aloft?
Physics
1 answer:
Dvinal [7]3 years ago
3 0

Answer:

4523.17365 Pa

Explanation:

m = Mass of plane = 77000 kg

F = Force = Weight = mg

g = Acceleration due to gravity = 9.81 m/s²

A = Total area of wings = 167 m²

The pressure difference would be

\Delta P=\dfrac{F}{A}\\\Rightarrow \Delta P=\dfrac{77000\times 9.81}{167}\\\Rightarrow \Delta P=4523.17365\ Pa

The pressure difference required to keep the plane aloft is 4523.17365 Pa

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The potential difference,electric current ,resistance and new electric current will be 12 V,4 A,3 Ω,2 A.

<h3>What is resistance?</h3>

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The energy in terms of the charge and potential difference is;

E= qV

60=5 C × V

V= 12 V

The electric current is found as;

\rm I= \frac{q}{t} \\\\ I= \frac{5}{1.25}\\\\ I=4 \ A

From the ohm's law;

V=IR

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If the voltage is constant and the resistance is doubled, then the new electric current is half of the previous condition;

\rm I'=\frac{I}{2} \\\\ I'=\frac{4}{2} \\\\\ I'=2 \ A

Hence, the potential difference,electric current ,resistance and new electric current will be 12 V,4 A,3 Ω,2 A.

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3 years ago
Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different direc
tankabanditka [31]

Answer:

a) 24.33 m of distance.

b) 34.55° east of the south.

Explanation:

The question is incomplete. The whole exercise is the following:

<em>"Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different directions. Ricardo walks 28.0 m in a direction 60.0° west of north. Jane walks 12.0 m in a direction 30.0° south of west. They then stop and turn to face each other. </em>

<em>(a) What is the distance between them? </em>

<em>(b) In what direction should Ricardo walk to go directly toward Jane?</em><em>"</em>

Now that we know what we need to do in this question, let's head for every part of the problem.

<u>a) Distance between Ricardo and Jane</u>

In this case, we need to analyze the given data:

Ricardo (which we will call R) is 28 m from the starting point at 60° west of north, and Jane (J) is 12 m at 30° south of west. So the distance between them, will be the point where they both stop and face each other. This point can be seen in the image attached (See picture).

Let's call the distance between them as "D", to get the distance of D, according to the picture will be:

D = J - R   (1)

However, as they are facing in different angles and directions, we cannot do the difference of their values distance just like that. In order to do that, we need to calculate the components in the "x" and "y" axis of each vector. In that way, we can get the components of x and y of the Distance D, and then, the whole distance between them will be:

D = √Dx² + Dy²     (2)

So, let's get the components of x and y of R and J.

For Ricardo (R):

Rx = R sin60° = 28 sin60° = -24.25 m

Ry = R cos60° = 28 cos60° = 14 m

The sign "-" it's because R it's on the second quadrant, therefore in x, we'll have to add the negative.

For Jane (J):

Jx = J cos30° = 12 cos30° = -10.39 m

Jy = J sin30° = 12 sin30° = -6 m

Again, the negative is added because J is on the third quadrant.

Now that we have the components, let's calculate vector D using expression (1):

Dx = -10.39 - (-24.25) = 13.86 m

Dy = -6 - 14 = -20 m

Now, using expression (2) we can finally know the distance between Jane And Ricardo:

D = √(-20)² + (13.86)²

<h2>D = 24.33 m</h2>

This is the distance between Jane and Ricardo.

b) Direction of Ricardo walking to Jane

In this case, we already have the components of x and y of the distance between them, so, to know the direction:

Tanα = Dy/Dx

α = tan⁻¹ (Dy/Dx)

Replacing the values we have:

α = tan⁻¹ (-20/13.86)

α = 55.45°

Which should south of east or:

β = 90 - 55.45

<h2>β = 34.55°</h2>

Ricardo should walk 34.55° east of south

Hope this helps

8 0
2 years ago
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