B because it’s got the least connections
Answer:
answer answer answer answer answer
It takes 33.4 s for the concentration of A to fall to one-fourth of its original value.
A <em>half-life</em> is the time it takes for the concentration to fall to half its original value.
Assume the initial concentration is 1.00 mol/L. Then,

The concentration drops to one-fourth of its initial value in two half-lives.
∴ Time = 2 × 16.7 s = 33.4 s
Answer:
526.85K
Explanation:
Based on Charles's law, the volume of a gas is directly proportional to absolute temperature. The formrula is:
V₁ / T₁ = V₂ / T₂
<em>Where 1 represents the initial state and 2 the final state of the gas</em>
Using the values of the problem:
V₁ = 10.0L
T₁ = 127°C + 273.15K = 400.15K
V₂ = 20.0L
Thus, replacing in the formula:
10.0L / 400.15K = 20.0L / T₂
T₂ = 800K
In Celsius:
800K - 273.15 =<em> 526.85K</em>
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