1. Assume this experiment (after the extractions are complete) left you with 4 pure products (aspirin, acetaminophen and caffein
1 answer:
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The overall reaction is given by:
The fast step reaction is given as:
The slow step reaction is given as:
(slow step
)
Now, the expression for the rate of reaction of fast reaction is:
The expression for the rate of reaction of slow reaction is:
Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as takes place in this reaction.
The expression of rate of formation is:
= (1)
Now, consider that the fast step is always is in equilibrium. Therefore,
Substitute the value of in equation (1), we get:
=
=
Thus, rate law of formation of in terms of reactants is given by
.
I believe this is it
