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3 years ago

5

calculate the magnitude of impulse applied to a 0.75 kilogram cart to change its velocity from 0.50 meters per second east to 2.

00 meters per second east

1 answer:

ella [17]3 years ago

8 0

Answer:

1.125 N s towards East

Explanation:

since both velocities are in same direction hence change in velocity is

Δ V = final - initial

= 2.00 - 0.50

= 1.50 towards East

impulse = change of linear momentum

= mass × change in velocity

= 0.75 ×1.50

= 1.125 N s towards East

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Answer:

h’ = 1/9 h

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This exercise must be solved in parts:

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madam [21]

Complete Question

The complete question is shown on the first uploaded image

Answer:

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Explanation:

From the question we are told that

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Generally the induced emf is mathematically represented as

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The maximum induced emf can also be represented mathematically as

$\epsilon_{max} = \frac{d \o}{dt}|_{max}$

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$\frac{d \o}{dt}|_{max} =26.8V$

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