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Illusion [34]
3 years ago
5

calculate the magnitude of impulse applied to a 0.75 kilogram cart to change its velocity from 0.50 meters per second east to 2.

00 meters per second east​
Physics
1 answer:
ella [17]3 years ago
8 0

Answer:

1.125 N s towards  East

Explanation:

since both velocities are in same direction  hence change in velocity is

Δ V = final - initial

       = 2.00 - 0.50

       = 1.50 towards East

impulse = change of linear momentum

             = mass ×  change in velocity

            =  0.75 ×1.50

          =  1.125 N s towards  East

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What are the benefits and drawbacks of using renewable energy sources to generate electricity?
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Answer:

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3 years ago
Calculate the force required to accelerate<br> a 600 g ball from rest to 14 m/s in 0.1 s.
Evgen [1.6K]

<u>Statement</u><u>:</u>

A force is required to accelerate a 600 g ball from rest to 14 m/s in 0.1 s.

<u>To </u><u>find </u><u>out</u><u>:</u>

The force required to accelerate the ball.

<u>Solution</u><u>:</u>

  • Mass of the ball (m) = 600 g = 0.6 Kg
  • Initial velocity (u) = 0 m/s [it was at rest]
  • Final velocity (v) = 14 m/s
  • Time (t) = 0.1 s

  • Let the acceleration be a.
  • We know the equation of motion,
  • v = u + at

  • Therefore, putting the values in the above formula, we get
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  • or, 14 m/s ÷ 0.1 s = a
  • or, a = 140 m/s²

  • Let the force be F.
  • We know, the formula : F = ma

  • Putting the values in the above formula, we get
  • F = 0.6 Kg × 140 m/s²
  • or, F = 84 N

<u>Answer</u><u>:</u>

The force required to accelerate the ball is 84 N and this force acts along the direction of motion.

Hope you could understand.

If you have any query, feel free to ask.

5 0
3 years ago
A satellite moves in a circular orbit at a constant speed v0 around Earth at a distance R from its center. The force exerted on
postnew [5]

Answer:

vT = v0/3

Explanation:

The gravitational force on the satellite with speed v0 at distance R is F = GMm/R². This is also equal to the centripetal force on the satellite F' = m(v0)²/R

Since F = F0 = F'

GMm/R² = m(v0)²/R

GM = (v0)²R  (1)

Also, he gravitational force on the satellite with speed vT at distance 3R is F1 = GMm/(3R)² = GMm/27R². This is also equal to the centripetal force on the satellite at 3R is F" = m(vT)²/3R

Since F1 = F'

GMm/27R² = m(vT)²/3R

GM = 27(vT)²R/3

GM = 9(vT)²R (2)

Equating (1) and (2),

(v0)²R = 9(vT)²R

dividing through by R, we have

9(vT)² = (v0)²

dividing through by 9, we have

(vT)² = (v0)²/9

taking square-root of both sides,

vT = v0/3

6 0
3 years ago
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