The magnitude of their resultant vector is 4.6 meters/seconds
Since we are to add the velocity vectors in order to find the magnitude of their resultant vector.
Hence:
Resultant vector magnitude=5.8 meters/seconds + (1.2 meters/seconds)
Resultant vector magnitude=5.8 meters/seconds-1.2 meters/seconds
Resultant vector magnitude 4.6 meters/seconds
Inconclusion The magnitude of their resultant vector is 4.6 meters/seconds
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Answer:
Energy= 46.08KJ
Explanation:
Given that the power needed to light each bulb is 32W
We know that Power = 
The energy needed to light one bulb=
Given time = 1minute = 60 seconds
Energy =
=1920J
Therefore energy needed to light one bulb is 1920J
The energy needed to light 24 bulbs =
=46080J=46.08KJ
The electrical force acting on a charge q immersed in an electric field is equal to

where
q is the charge
E is the strength of the electric field
In our problem, the charge is q=2 C, and the force experienced by it is
F=60 N
so we can re-arrange the previous formula to find the intensity of the electric field at the point where the charge is located:
Answer: 22.6 hours
Explanation:
The power is the measure of the rate of energy.
In this problem, the 12.0 V battery is rated at 51.0 Ah, which means it delivers 51.0 A of current in a time of t = 1 h = 3600 s. The power delivered by the battery can be written as

where
I is the current
V = 12.0 V is the voltage of the battery
So the energy delivered by the battery can be written as

Where

So the energy delivered is

At the same time, the headlight consumes 27.0 W of power, so 27 Joules of energy per second; Therefore, it will remain on for a time of:
