Kinetic or potential energy
1 answer:
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Answer: The ratio of f at the higher temperature to f at the lower temperature is 4.736
Explanation:
According to the Arrhenius equation,
or,
where,
= rate constant at 525K
= rate constant at 545K
= activation energy for the reaction = 185kJ/mol= 185000J/mol (1kJ=1000J)
R = gas constant = 8.314 J/mole.K
= initial temperature = 525 K
= final temperature = 545 K
Now put all the given values in this formula, we get
Therefore, the ratio of f at the higher temperature to f at the lower temperature is 4.736
Answer:
Explanation:
Given that,
Force acting on an object, F = 30 N
Mass of the object, m = 4 kg
It is moving with a constant velocity of 2 m/s across a level surface.
We need to find the coefficient of friction between the object and the surface. Let it is μ. Force in terms of coefficient of friction is given by :
F = μ N, Where N is normal force, N = mg
So, the coefficient of friction between the object and the surface is 0.75.