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MAVERICK [17]
2 years ago
12

The diffraction limit is a limit on: The diffraction limit is a limit on: A telescope's size. A telescope's angular resolution.

A telescope's spectral resolution.
Physics
1 answer:
Mnenie [13.5K]2 years ago
7 0

Answer:

A telescope's angular resolution.

Explanation:

Diffraction limit is a minimum angular separation of two sources and it can be distinguished by the telescope. This angle is known as the diffraction limit. It is proportional to the wavelength of light and it has an inverse relation with the diameter of the telescope. Mathematically  it is defined as

θ = 1.22λ/d

where θ is the angle, λ wavelength and d is the diameter of the objective mirror (lenz).

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Which will remain the same for two identical books, one lying flat and the other standing on an end?
Fiesta28 [93]

Weight will remain the same for two identical books, one lying flat and the other standing on an end.

The strain at a factor internal a liquid is at once proportional to the intensity of the factor. When an item is submerged in a liquid, the intensity of its backside from the floor of the liquid is extra than that of some other a part of the item.

Archimedes' precept is the declaration that the buoyant pressure on an item is identical to the load of the fluid displaced with the aid of using the item.

Ensure your scale is on a flat, strong and stage floor. Do now no longer use your scale on carpet. When taking measurements, stand nevertheless withinside the middle of the platform till all measurements are displayed, and if feasible do now no longer circulate your scale in-among measurements.

Learn more about weight here brainly.com/question/229459

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8 0
8 months ago
A radio wave has a speed of 3.00 x10^8 and a frequency of 100 MHz. What is the wavelength?
dlinn [17]

Answer:

Wavelength of radio is wave is 3 m

Explanation:

Wavelength of radio is wave is

\lambda=\frac{v}{f}

where

v=3 \times 10^8 m\s\\f=100 Mhz

wavelength is

\lambda=\frac{3\times 10^8}{100\times 10^6} \\\\\lambda=3 m\\

5 0
2 years ago
Paola can flex her legs from a bent position through a distance of 20.1 cm. Paola leaves the ground when her legs are straight,
makkiz [27]

The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/s^{2}.

Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.

To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e V^{2} = U^{2} ± 2as

where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.

From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

So that since Poala flies against gravity, then we have:

V^{2} = U^{2} - 2as

0 = (4)^{2} - 2(a x 0.201)

  = 16 - 0.402a

0.402a = 16

a = \frac{16}{0.402}

  = 39.801

a = 39.80 m/s^{2}

Therefore Paola's acceleration is 39.80 m/s^{2}.

Visit: brainly.com/question/17493533

7 0
2 years ago
Read 2 more answers
The electric force between two charged balloons is 0.12 newtons. If the distance between the two balloons is halved, what will b
marshall27 [118]

Answer:

The answer is D, I just took the test

Explanation:

5 0
3 years ago
While in empty space, an astronaut throws a ball at a velocity of 11 m/s. what will the velocity of the ball be after it has tra
Aliun [14]
In empty space probably means, there is no force on the ball.

(This assumption is not quite correct since there is still the force of gravity between the ball and the astronaut, but this force is very very small and can be neglected.)

Assuming there is no force on the ball, Newtown's 1st law says: When viewed in an internal frame of reference, an object either remains at rest or continues to move at a constant velocity, unless acted upon by a force.
 
This means:
If there is no force on the ball, there will be no acceleration on the ball either.
If the acceleration is zero, the velocity of the ball never changes.
3 0
3 years ago
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