Answer:
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Answer:
Shearing strain will be 0.1039 radian
Explanation:
We have given change in length 
Length of the pad L = 1.15 inch
We have to find the shearing strain
Shearing strain is given by

Shearing strain is always in radian so we have to change angle in radian
So 
Answer:
13.4 mm
Explanation:
Given data :
Load amplitude ( F ) = 22,000 N
factor of safety ( N )= 2.0
Take ( Fatigue limit stress amplitude for this alloy ) б = 310 MPa
<u>calculate the minimum allowable bar diameter to ensure that fatigue failure will not occur</u>
minimum allowable bar diameter = 13.4 * 10^-3 m ≈ 13.4 mm
<em>attached below is a detailed solution</em>
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.