Whoa never done physics looks hard tho
Answer:
Time period of the osculation will be 0.0671 sec
Explanation:
It is given a vertical spring is stretched by 4 cm
So change in length of the spring x = 4 cm = 0.04 m
Mass which is hung from it m = 12 gram = 0.012 kg
Sprig force will be equal to weight of the mass
So 
k = 244.7 N/m
Now new mass is m = 28 gram = 0.028 kg
So time period with new mass will be
Nearly all light that strikes a transparent object will be absorbed by the object.
Answer:
a) x = 660 m
, b) λ = 0.330 m
, c) precision is 0.1 cm
, d) Δf= n Δt/ t²
Explanation:
a) the speed of sound is constant, therefore we can use the relation of motion to inform the distance that the sound extends is
v = x / t
x = v t
x = 330 2
x = 660 m
b) the speed of sound is
v = λ f
λ = v / f
λ = 330/1000
λ = 0.330 m
c) a measuring tape must be used to measure the wavelength, the precision is 0.1 cm
.d) frequency measurement is more delicate, a stopwatch should be used to measure a certain number of oscillations, and hence calculate the frequency
.f = n / t
Therefore, if we assume that there is no error in the number of oscillations, the pressure is given by the appreciation of the stopwatch, which is maximum 0.01 s
Δf / f = Δt / t
Δf = Δt /t f
Δf= n Δt/ t²
