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astraxan [27]
2 years ago
14

A magnet has ___________ poles. Like poles__________each other and unlike poles __________. An electromagnet is used to separate

large masses of___________ scrap. The strength of the magnetic is increased by inserting a _____________. In torch we use a ________ as the source of electricity. To light a table lamp and to run a refrigerator, We use ____________ as the source of electricity. A group or two or more cells is called a ___________ . _____________ pass electricity through them.
Physics
2 answers:
NARA [144]2 years ago
4 0

Answer:

A magnet has two poles.

Like poles repel each other and unlike poles attract

An electromagnet is used to separate large masses of iron scrap.

The strength of the magnetic field of an electromagnet is increased by inserting a core of soft iron.

In a torch we use a dry cell as the source of electricity.

To light a table lamp and to run a refrigerator, we use mains as the source of electricity.

A group of two or more cells is called a battery.

Conductors pass electricity through them.

Stels [109]2 years ago
3 0

Answer:

2 repel attracts light water

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How many grams are in 6.53 moles of Mn?
Westkost [7]

Answer:

359 g Mn

General Formulas and Concepts:

  • Dimensional Analysis
  • Reading the Periodic Table of Elements

Explanation:

<u>Step 1: Define</u>

6.53 mol Mn

<u>Step 2: Find conversion</u>

1 mol Mn = 54.94 g Mn

<u>Step 3: Dimensional Analysis</u>

<u />6.53 \hspace{3} mol \hspace{3} Mn(\frac{54.94 \hspace{3} g \hspace{3} Mn}{1 \hspace{3} mol \hspace{3} Mn} ) = 358.758 g Mn

<u>Step 4: Simplify</u>

<em>We are given 3 sig figs.</em>

358.758 g Mn ≈ 359 g Mn

3 0
2 years ago
A car moved 120km to the north. what is its displacement?
inn [45]
120Km. They are the same
5 0
3 years ago
A red train travelling at 72 km/h and a green train travelling at 144 km/h are headed toward each
abruzzese [7]

Answer:

  Collision will occur.

  Speed of red train when they collide = 0 m/s.

  Speed of green train when they collide = 10 m/s.

Explanation:

Speed of red train = 72 km/h = 20 m/s

Speed of green train = 144 km/h = 40 m/s.

Deceleration of trains = 1 m/s²

For red train:-

    Equation of motion v = u + at

              u = 20 m/s

              v = 0 m/s

              a = -1 m/s²

    Substituting

             0 = 20 - 1 x t

             t = 20 s.

    Equation of motion s = ut + 0.5at²

              u = 20 m/s

              t = 20 s

              a = -1 m/s²    

    Substituting

             s = 20 x 20 - 0.5 x 1 x 20² = 200 m

   So red train travel 200 m before coming to stop.

For green train:-

    Equation of motion v = u + at

              u = 40 m/s

              v = 0 m/s

              a = -1 m/s²

    Substituting

             0 = 40 - 1 x t

             t = 40 s.

    Equation of motion s = ut + 0.5at²

              u = 40 m/s

              t = 40 s

              a = -1 m/s²    

    Substituting

             s = 40 x 40 - 0.5 x 1 x 40² = 800 m

   So green train travel 800 m before coming to stop.

 Total distance traveled = 800 + 200 = 1000 m>950 m.

  So both trains collide.

  Distance traveled by green train when red train stops(t=20s)

     Equation of motion s = ut + 0.5at²

              u = 40 m/s

              t = 20 s

              a = -1 m/s²    

    Substituting

             s = 40 x 20 - 0.5 x 1 x 20² = 600 m

    Total distance after 20 s = 600 + 200 = 800 m< 950m . So they collide after red train stops.

  Speed of red train when they collide = 0 m/s.

  Distance traveled by green train when they collide = 950 - 200 = 750 m

  Equation of motion v² = u² + 2as

              u = 40 m/s

              s= 750 m

              a = -1 m/s²    

    Substituting  

              v² = 40² - 2 x 1 x 750 = 100

               v = 10 m/s

  Speed of green train when they collide = 10 m/s.

6 0
3 years ago
Does poop come out the pp or the butt please help im so confused best awnser gets brainleist
natulia [17]

Answer:

no poop comes out from your but

Explanation:

5 0
2 years ago
Read 2 more answers
Assume that you have a rectangular tank with its top at ground level. The length and width of the top are 14 feet and 7 feet, re
ch4aika [34]

To solve this problem we will use the work theorem, for which we have that the Force applied on the object multiplied by the distance traveled by it, is equivalent to the total work. From the measurements obtained we have that the width and the top are 14ft and 7ft respectively. In turn, the bottom of the tank is 15ft. Although the weight of the liquid is not given we will assume this value of 62 lb / ft ^ 3 (Whose variable will remain modifiable until the end of the equations subsequently presented to facilitate the change of this, in case be different). Now the general expression for the integral of work would be given as

W = \gamma A * \int_0^15 dy

Basically under this expression we are making it difficult for the weight of the liquid multiplied by the area (Top and widht) under the integral of the liquid path to be equivalent to the total work done, then replacing

W = (62)(14*7)\int^{15}_0 (15-y)dy

W = (14*7*62)\big [15y-\frac{y^2}{2}\big ]^{15}_0

W = (14*7*62)[15(15)-\frac{(15)^2}{2}]

W = 683550ft-lbs

Therefore the total work in the system is 683550ft-lbs

6 0
3 years ago
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