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alexandr1967 [171]
3 years ago
11

Which best explains why elements with a completely full outer shell of electrons do not usually bond with other elements to form

compounds?
A.
A full outer shell of electrons indicates a stable state, making the formation of compounds unnecessary. The full outer shell was obtained by releasing electrons instead of forming a compound.

B.
These elements have obtained electrons from other elements without bonding to create a full outer shell of electrons, and a stable state.

C.
Elements with a completely full outer shell of electrons are in their most stable state. Therefore, achieving stability through the formation of compounds is not necessary.

D.
Because electrons orbit some atoms in three dimensional space, they move to different orbitals to stabilize the atom, making the formation of compounds unnecessary.
explain.
Physics
1 answer:
Alla [95]3 years ago
8 0

The best answer is C.

The stability of atoms depends on whether or not their outermost shell is filled with electrons. If the outer shell is filled with electrons, the atom is stable and therefore they do not need to react  with other elements to become stable.

On the other hand, atoms with unfilled outer shells are unstable, and will usually form chemical bonds with other atoms to achieve stability. To achieve stability, atoms will form two types of chemical  bonds called ionic bonds and covalent bonds.





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Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving -1.72 m/s. What is the veloc
Nuetrik [128]

The velocity of B after elastic collision is 3.45m/s

This type of collision is an elastic collision and we can use a formula to solve this problem.

<h3>Elastic Collision</h3>

v_2 = \frac{2m_1u_1}{m_1+m_2} - \frac{m_1 - m_2}{m_1 + m_2}u_2

The data given are;

  • m1 = 281kg
  • u1 = 2.82m/s
  • m2 = 209kg
  • u2 = -1.72m/s
  • v1 = ?

Let's substitute the values into the equation.

v_1 = \frac{2*281*2.82}{281+209} -\frac{281-209}{281+209}(-1.72)\\v_1 = 3.45m/s

From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.

Learn more about elastic collision here;

brainly.com/question/7694106

4 0
2 years ago
A uniform solid disk and a uniform hoop are placed side by side at the top of an incline of height h. If they are released from
tigry1 [53]

Answer:

The disk will reach the bottom first.

Explanation:

As we know:

change in kinetic energy = change in potential energy

                                   ΔK.E = -ΔP.E

                             \frac{1}{2} mv^{2} + \frac{1}{2}Iw^{2}  = Mgh

                                Mv^{2} +I\frac{v^{2} }{R^{2} } = 2Mgh

                           v=\sqrt{\frac{2Mgh}{M+\frac{I}{R^{2} } } }

For the disk:

I=\frac{MR^{2} }{2}

For Hoop:

I=MR^{2}

Hence

Velocity for the disk:

v=\sqrt{\frac{4}{3}gh }

Velocity for the Hoop:

v=\sqrt{gh}

8 0
3 years ago
Pressure and volume changes at a constant temperature can be calculated using
Crank
It can be calculated using Boyle's Law.  A.
3 0
3 years ago
What does this meannn plsssssss
VARVARA [1.3K]

Answer:

the answer is B

Hope this helps!

Have a nice day :)

Explanation:

6 0
3 years ago
Read 2 more answers
Can anyone please tell me the properties of image formed in a spherical mirror?
notsponge [240]

Answer:

The two rays, CY and DM are diverging rays and when extended behind the mirror, they appear to intersect each other at point M'. Therefore, the properties of the images formed here are formed behind the mirror, between the pole and principal focus (f), the images are diminished and are virtual and erect.

Explanation:

<h2>Spherical Mirrors</h2>

  • There are two kinds of spherical mirrors, concave and convex.

  • The focal point (F) of a concave mirror is the point at which a parallel beam of light is "focussed" after reflection in the mirror. ...

  • The focal length (f) and radius of curvature (R) are defined in the diagram at the right.

<h3>hope it helps and thanks for following </h3><h2>please give brainliest </h2>
6 0
3 years ago
Read 2 more answers
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