What are you asking here?
Answer:
34.3 m/s
Explanation:
Newton's Second Law states that the resultant of the forces acting on the car is equal to the product between the mass of the car, m, and the centripetal acceleration
(because the car is moving of circular motion). So at the top of the hill the equation of the forces is:

where
(mg) is the weight of the car (downward), with m being the car's mass and g=9.8 m/s^2 is the acceleration due to gravity
R is the normal reaction exerted by the road on the car (upward, so with negative sign)
v is the speed of the car
r = 0.120 km = 120 m is the radius of the curve
The problem is asking for the speed that the car would have when it tires just barely lose contact with the road: this means requiring that the normal reaction is zero, R=0. Substituting into the equation and solving for v, we find:

Answer:
"0.049 W" is the correct answer.
Explanation:
According to the given question,



As we know,
⇒ 


Now,
⇒ 



or,

Answer:

Explanation:
The period of a simple pendulum is given by the equation

where
L is the lenght of the pendulum
g is the acceleration due to gravity at the location of the pendulum
We notice from the formula that the period of a pendulum does not depend on the mass of the system
In this problem:
-The pendulum comes back to the point of release exactly 2.4 seconds after the release. --> this means that the period of the pendulum is
T = 2.4 s
- The length of the pendulum is
L = 1.3 m
Re-arranging the equation for g, we can find the acceleration due to gravity on the planet:

Answer:
Balancing of forces,
In the X-direction:
-Tcos4.5^o +Tcos4.5^o=0
In the Y-direction:
Tsin4.5^o +Tsin4.5^o-m*g=0
2Tsin4.5^o=15*9.81
T=(15*9.81)/(2sin4.5^o)
=937.75 N
Therefore, tension in the rope is 937.75 N.