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sertanlavr [38]
4 years ago
14

What are laws of Physics?

Physics
1 answer:
Luba_88 [7]4 years ago
8 0
The basic laws of physics fall into two categories: classical physics that deals with the observable world (classical mechanics), and atomic physics that deals with the interactions between elementary and sub atomic particles (quantum mechanics).
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A blank is a statement the summerizes a pattern found in nature
MrMuchimi
What are you asking here?
4 0
3 years ago
A car drives over a hilltop that has a radius of curvature 0.120 km at the top of the hill. At what speed would the car be trave
Mashutka [201]

Answer:

34.3 m/s

Explanation:

Newton's Second Law states that the resultant of the forces acting on the car is equal to the product between the mass of the car, m, and the centripetal acceleration a_c (because the car is moving of circular motion). So at the top of the hill the equation of the forces is:

mg-R = m a_c = m\frac{v^2}{r}

where

(mg) is the weight of the car (downward), with m being the car's mass and g=9.8 m/s^2 is the acceleration due to gravity

R is the normal reaction exerted by the road on the car (upward, so with negative sign)

v is the speed of the car

r = 0.120 km = 120 m is the radius of the curve

The problem is asking for the speed that the car would have when it tires just barely lose contact with the road: this means requiring that the normal reaction is zero, R=0. Substituting into the equation and solving for v, we find:

v=\sqrt{gr}=\sqrt{(9.8 m/s^2)(120 m)}=34.3 m/s

6 0
3 years ago
A loudspeaker, mounted on a tall pole, is engineered to emit 75% of its sound energy into the forward hemisphere, 25% toward the
Naily [24]

Answer:

"0.049 W" is the correct answer.

Explanation:

According to the given question,

r = \sqrt{(3.5)^2+(2.5)^2}

  =\sqrt{8.5}

SL=85

As we know,

⇒  SL=10 \ log(\frac{I}{I_o} )

     85=10 \ log(\frac{I}{10^{-12}} )

      I=3.162\times 1^{-4} \ W/m^2

Now,

⇒  P_{front} = I(2\pi r^2)

               =(3.162\times 10^{-4})(2\pi\times 18.5)

               =0.0368 \ W

               =0.75 \ P

or,

                =0.049 \ W

7 0
3 years ago
Please answerASAP
Illusion [34]

Answer:

8.9 m/s^2

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the lenght of the pendulum

g is the acceleration due to gravity at the location of the pendulum

We notice from the formula that the period of a pendulum does not depend on the mass of the system

In this problem:

-The pendulum comes back to the point of release exactly 2.4 seconds after the release. --> this means that the period of the pendulum is

T = 2.4 s

- The length of the pendulum is

L = 1.3 m

Re-arranging the equation for g, we can find the acceleration due to gravity on the planet:

g=(\frac{2\pi}{T})^2 L=(\frac{2\pi}{2.4})^2(1.3)=8.9 m/s^2

7 0
4 years ago
A muscle builder holds the ends of a masslessrope. At the
Grace [21]

Answer:

Balancing of forces,

In the X-direction:

-Tcos4.5^o +Tcos4.5^o=0

In the Y-direction:

Tsin4.5^o +Tsin4.5^o-m*g=0

2Tsin4.5^o=15*9.81

T=(15*9.81)/(2sin4.5^o)

=937.75 N

Therefore, tension in the rope is 937.75 N.

7 0
3 years ago
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