Multiply the mass by the abundance and add each. Make sure to convert the percentage into a decimal. (49.946 * .043) + (51.941 * .838) + (52.941 * .095) + (53.939 * .024) = 51.99 round up using sig figs and the answer is c. 52.00 amu
Answer:
1g = 6.022 x 1023 AMU
Explanation:
An atomic mass unit or AMU is a physical constant which is equal to one-twelfth of the mass of an unbound carbon-12 atom.
One unified atomic mass unit is equal to 1.66 yoctograms = 1.66053904020 x 10-24 g.
1 AMU is equivalent to 1.66 x 10-24 grams and 1 gram is equivalent to 6.022 x 1023 AMU.
Thus,1g = 6.022 x 1023 AMU.
Missing question: <span>Assume a density of 10.35 g/cm3 for Ag, A(Ag) = 107.87 g/mol.
N(Ag) = Na </span>· d(Ag) ÷ A(Ag).
N(Ag) = 6,023·10²³ atoms/mol · 10,35 g/cm³ · 10⁶ cm³/m³ ÷ 107,87 g/mol.
N(Ag) = 5,78·10²⁸ atoms/mol.
Nv = 5,78·10²⁸ atoms/mol · 5·10⁻⁵.
Nv = 2,89·10²².
At room temperatures, elements lithium, sodium, rubidium,
barium, vanadium, chromium and iron have structures that can be described as a
body center cubic packing of spheres. The packing fraction of a body center
cubic cell is 0.68.
Answer:
<h2>20 kg</h2>
Explanation:
The mass of the football can be found by using the formula
f is the force
a is the acceleration
From the question we have
We have the final answer as
<h3>20 kg</h3>
Hope this helps you