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Lisa [10]
3 years ago
9

Focal Lengths II If you were handed an unmarked convex lens (no optical track) and asked to estimate its focal length quickly, h

ow would you do it? Explain.
Physics
1 answer:
Lapatulllka [165]3 years ago
5 0

Answer:

Explanation:

To estimate the focal length of a convex lens follow the following steps.

1. take a convex lens.

2. Stand near a window which is just opposite to a wall.

3. Look at a tree which is far away from the window by the convex lens.

4. focus the image of the tree on the wall which is opposite to the window.

5. You wll observe that by changing the position of convex lens a sharp and inverted and small image is seen on the wall.

5. Now measure the distance between the lens and the wall.

7. This distance is the rough focal length of the convex lens.

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Which statement best describes how today’s scientific community views light?
Anna11 [10]

Light behaves like both waves and particles.

4 0
4 years ago
Read 2 more answers
A grocery shopper tosses a(n) 9.1 kg bag of
spin [16.1K]

Answer:

2.1 m/s

Explanation:

Momentum is conserved, so:

m₁ u₁ + m₂ u₂ = (m₁ + m₂) v

(9.1 kg) (6.6 m/s) = (9.1 kg + 19.3 kg) v

v = 2.1 m/s

3 0
3 years ago
1.- Un barco recorre la distancia que separa Gran Canaria de Tenerife (90 km) en 6 horas. ¿Cuál es
bezimeni [28]

Answer:

The speed is 15 km/h or 4.16 m/s.

Explanation:

A boat travels the distance that separates Gran Canaria from Tenerife (90 km) in 6 hours. Which  the speed of the boat in km / h? And in m / s?

Given that,

Distance, d = 90 km = 90000 m

Time, t = 6 hours = 21600 s

Speed = distance/time

v=\dfrac{90\ km}{6\ h}\\\\=15\ km/h

or

v=\dfrac{90000\ m}{21600\ s}\\\\=4.16\ m/s

So, the required speed is 15 km/h or 4.16 m/s.

7 0
3 years ago
PLEASE HELP
Ronch [10]
Seems the both of us haven't done the project yet.
6 0
3 years ago
A pair of electrically charged objects attract each other with a force of 4 N when they are a distance of 3 m apart. If their ch
Rainbow [258]

Answer:

1 N

Explanation:

From coulomb's law,

The force of attraction between two charges is inversely proportional to the square of the distance between the charges.

From the question,

Assuming the charges are the same in both case,

F ∝ /r²....................... Equation 1

Fr² = k

F'r'² = Fr²........................... Equation 2

Where F' = First Force, r'² = First distance, F = second force, r² = second distance.

make F the subject of the equation,

F = F'r'²/r².................... Equation 3

Given: F' = 4 N, r' = 3 m, r = 6 m

Substitute into equation 3

F = 4(3²)/6²

F = 36/36

F = 1 N

7 0
3 years ago
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