1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fomenos
4 years ago
12

the time required for one cycle, a complete motion that returns to its starting point, it called the_____. period medium frequen

cy periodic motion
Physics
1 answer:
Salsk061 [2.6K]4 years ago
3 0

Answer:

The time required for one cycle, a complete motion that returns to its starting point,it is called periodic motion

Explanation:

I hope this will help you:)

You might be interested in
The coefficient of cubical expansion of a substance depends upon
zzz [600]
<span>I think that the coefficient of cubical expansion of a substance depends on THE CHANGE IN VOLUME.

Cubical expansion, also known as, volumetric expansion has the following formula:

</span>Δ V = β V₁ ΔT

V₁ = initial volume of the body
ΔT = change in temperature of the body
β = coefficient of volumetric expansion.

β is defined as the <span>increase in volume per unit original volume per Kelvin rise in temperature.
</span>
With the above definition, it is safe to assume that the <span>coefficient of cubical expansion of a substance depends on the change in volume, which also changes in response to the change in temperature. </span>
7 0
3 years ago
A horizontal spring with spring constant 130 N/m is compressed 17 cm and used to launch a 2.8 kg box across a frictionless, hori
olasank [31]

Explanation:

The given data is as follows.

        k = 130 N/m,       \Delta x = 17 cm = 0.17 m   (as 1 m = 100 cm)

     mass (m) = 2.8 kg

When the spring is compressed then energy stored in it is as follows.

             Energy = \frac{1}{2}kx^{2}

Now, spring energy gets converted into kinetic energy when the box is launched.

So,    \frac{1}{2}kx^{2} = \frac{1}{2}mv^{2}

   \frac{1}{2} \times 130 \times (0.17)^{2} = \frac{1}{2} \times 2.8 \times v^{2}

          v^{2} = \frac{3.757}{2.8}

                     = 1.34

                v = 1.15 m/sec

Now,

           Frictional force = \mu \times mg

                                    = 0.15 \times 2.8 \times 9.8

                                    = 4.116 N

Also,  Kinetic energy = work done by friction

           \frac{1}{2}mv^{2} = F_{f} \times d

           \frac{1}{2} \times 2.8 \times (1.15)^{2} = 4.116 \times d

             1.8515 = 4.116 \times d

                 d = 0.449 m

Thus, we can conclude that the box slides 0.449 m across the rough surface before stopping.

8 0
3 years ago
On what principle does a bottle opener work
Vsevolod [243]

Answer:

Bottle opener works on a fulcrum.

Explanation:

A bottle opener is a second-class lever because the pivot point is at one end of the opener and the load is in the middle.

8 0
3 years ago
How to make a paper airplane curve down and fly upside down?
Ainat [17]
Throw it sideways and try to make it spin around but it needs to be thrown high up then it should kinda glide down
8 0
3 years ago
Read 2 more answers
Una tortuga se desplaza en línea recta 100cm al norte y luego 80cm al este, determine su desplazamiento
valentinak56 [21]

Answer:

is this the full question?

5 0
3 years ago
Other questions:
  • Can you give me some project ideas
    5·1 answer
  • What is the “lag of seasons”?
    5·1 answer
  • Explain how a battery in a circuit is similar to a water pump.
    14·1 answer
  • A driver in a car traveling at a speed of 26.8 m/s sees a deer 100 m away on the road. Calculate the minimum constant accelerati
    11·1 answer
  • Who invented abstract geometry
    8·2 answers
  • What is the difference between condensation and conduction
    5·1 answer
  • What is the maximum speed with which a 1200-kg car can round a turn of radius 94.0 m on a flat road if the coefficient of static
    8·1 answer
  • Chapter 05, Problem 15 Multiple-Concept Example 7 and Concept Simulation 5.2 review the concepts that play a role in this proble
    12·1 answer
  • A hummingbird can flap its wings 200 Hz times per second. If the hummingbird produces waves that travel at 340 m/s by flapping i
    6·1 answer
  • 1 point<br> How much force is needed to accelerate an 84-kg boulder at a rate of 6.4<br> m/s/s? *
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!