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rodikova [14]
3 years ago
14

Is powdered sports drink ionic or covalent ? 10pts !

Chemistry
1 answer:
Dahasolnce [82]3 years ago
7 0
<h3><u>Answer;</u></h3>

Ionic

Powdered sports drink is<u> ionic </u>

<h3><u>Explanation;</u></h3>
  • <em><u>Sports drinks are beverages whose purpose is to help athletes replace water, electrolytes, and energy before and after training or competition.</u></em>
  • Sport drinks contain may contain water, fuel and electrolytes which are used to regulate fluid balances in the body. Electrolytes are molecules that have electrical charge called ions, such as calcium , potassium, sodium and chloride ions.
  • <em><u>Ionic compounds are made up of ions, that is positively charged ions and negatively charged ions which are joined together by ionic bonds. Electrolyte in sport drinks forms ionic bonds.</u></em>
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stira [4]

Answer:

m

Explanation:

m

5 0
3 years ago
How to find hydrogen ion concentration from molarity of solution
vekshin1

The concentration of the hydrogen ions from molarity can be given with the number of hydrogen atoms in the molecular formula.

<h3>What is molarity?</h3>

Molarity is given as the moles of the solute present in a liters of solution. The compound with the number of hydrogen atoms in the molecular formula with degradation possesses the equivalent concentration of the hydrogen ions.

The compound with molecular formula AH having molarity 2, will produce 2M of hydrogen ions.

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7 0
2 years ago
(f) Which of the following alkenes is the major product when 2-bromo-2-methylpentane is treated with sodium ethoxide in ethanol?
belka [17]

Answer:

D) 2-methylpent-2-ene

Explanation:

This is an elimination reaction of Halogenoalkane. 2-bromo-2-methylpentane when is heated with NaOH or NaOC2O5( sodium ethoxide) in ethanol will form alkene rather than alcohol.

2-methylpent-1-ene is minor product since double bond form with secondary Carbon rather than primary Carbon.

8 0
3 years ago
Read 2 more answers
What is the most soluble salt of the following set? What is the most soluble salt of the following set?
DiKsa [7]

Answer:

(c) AgCN\ (K_{sp} =6.0\times 10^{-17})

Explanation:

The solubility product of a solid is the amount of solid dissociates into its respective ions in the solution. Thus more the value of the Ksp, the more is the salt soluble in the solvent.

So,  Given that:-

Sn(OH)_2\ (K_{sp} =1.6\times 10^{-19})

Al(OH)_3\ (K_{sp} =1.9\times 10^{-33})

AgCN\ (K_{sp} =6.0\times 10^{-17})

Fe(OH)_3\ (K_{sp} =2.6\times 10^{-39})

The salt having highest value of Ksp is AgCN. So, it is most soluble.

4 0
3 years ago
Given 7.40 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100
Dafna11 [192]
On complete conversion (100% yield) 9.75 g of ethyl butyrate will be produced. Below is the solution.....

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4 years ago
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