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IRISSAK [1]
4 years ago
14

What two factors determine the energy production of the Hoover Dam

Physics
2 answers:
swat324 years ago
6 0
Mar 28, 2011 · The Hoover Dam generates electricity using hydropower. Hydropower is the power generated by moving water. Dams are often built on a large river, so the water falls down from the top of the dam. At the bottom of the dam, the water rotates a large turbine

Hope this helps :p
scZoUnD [109]4 years ago
4 0

Answer:

Two factors are water speed and amount of water.

Explanation:

The production of hydro electrical power can be done when the water passes from the dam to the rivers which are below dam.

Turbines which are surrounded by magnets produce the electricity when the flowing water is hit on the turbines than turbines rotates and produce electricity and turbines are present in the dam.

The energy production of the Hoover dam is based on the amount or pressure of the water if the more water is passing through the intake pipe then there is more production of energy. An artificial lake is created behind the dam.

And energy production also depends on the speed of water means if the speed of water is large then it rotate the turbine faster and increase the production.

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When a heavy football player and a light one run into each other, which player hits the other with more force? Explain. Which on
EleoNora [17]

Answer:

When a heavy football player and a light one run into each other, does the lighter player really exert as much force on the heavy player s the heavy player exerts on the light one. Yes. The interaction between the two players, the force each exerts on the other have equal strength.

7 0
3 years ago
Which property of a body resists change from a state of rest or of motion?
jeyben [28]

Answer:

mass

Explanation:

As this is directly related to inertia. Inertia is the property of unit which resists the change of state of rest or motion

7 0
2 years ago
Read 2 more answers
The u.s has sent unmanned spacecrafts to ___ the planets in our solar system
kirill115 [55]
I think it's C. if we're talking about a rover.

But if it's a rocket that's computerized and automatic (synonym of unmanned)... Then it's B.
6 0
3 years ago
Read 2 more answers
Party hearing. As the number of people at a party increases, you must raise your voice for a listener to hear you against the ba
dusya [7]

Answer:

\frac{r_i}{1.77} m

Explanation:

Given that

At starting separated = 1.20m

And the increase in background noise by Δβ = 5 dB, due to which the level of sound also rises

Based on the above information, the separation rf that is needed is shown below:

As we know that

I_f = I_o \times 10^{\frac{\beta}{10} }\\\\I_f = I_i \times 10^{0.5}\\\\I_f = 3.16 \times  I_i\\\\I \alpha \frac{1}{r^2} \\\\\frac{r_i^2}{r_f^2} = 3.16\\\\r_f = \frac{\sqrt{r_i^2}}{{\sqrt3.16}} \\\\= \frac{r_i}{1.77} m

Hence, the separation r_f i.e. required is  \frac{r_i}{1.77} m

We simply applied the above equation so that the correct separation could come

6 0
3 years ago
A ball is in free fall after being dropped. What willthe speed of the ball be after 2 seconds of free fall?
Mazyrski [523]

So, the speed of the ball after 2 seconds after free fall is <u>20 m/s</u>.

<h3>Introduction</h3>

Hi ! I'm Deva from Brainly Indonesia. In this material, we can call this event "Free Fall Motion". There are two conditions for free fall motion, namely falling (from top to bottom) and free (without initial velocity). Because the question only asks for the final velocity of the ball, in fact, we may use the formula for the relationship between acceleration and change in velocity and time. In general, this relationship can be expressed in the following equation :

\boxed{\sf{\bold{a = \frac{v_2 - v_1}{t}}}}

With the following conditions :

  • a = acceleration (m/s²)
  • \sf{v_2} = speed after some time (m/s)
  • \sf{v_1} = initial speed (m/s)
  • t = interval of time (s)

<h3>Problem Solving</h3>

We know that :

  • a = acceleration = 9,8 m/s² >> because the acceleration of a falling object is following the acceleration of gravity (g).
  • \sf{v_1} = initial speed = 0 m/s >> the keyword is free fall
  • t = interval of time = 2 s

What was asked :

  • \sf{v_2} = speed after some time = ... m/s

Step by step :

\sf{a = \frac{v_2 - v_1}{t}}

\sf{(a \times t) + v_1 = v_2}

\sf{(10 \times 2) + 0 = v_2}

\boxed{\sf{v_2 = 20 \: m/s}}

So, the speed of the ball after 2 seconds after free fall is 20 m/s.

8 0
2 years ago
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