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4 years ago

What two factors determine the energy production of the Hoover Dam

2 answers:

swat324 years ago

6 0

Mar 28, 2011 · The Hoover Dam generates electricity using hydropower. Hydropower is the power generated by moving water. Dams are often built on a large river, so the water falls down from the top of the dam. At the bottom of the dam, the water rotates a large turbine

Hope this helps :p

scZoUnD [109]4 years ago

4 0

Answer:

Two factors are water speed and amount of water.

Explanation:

The production of hydro electrical power can be done when the water passes from the dam to the rivers which are below dam.

Turbines which are surrounded by magnets produce the electricity when the flowing water is hit on the turbines than turbines rotates and produce electricity and turbines are present in the dam.

The energy production of the Hoover dam is based on the amount or pressure of the water if the more water is passing through the intake pipe then there is more production of energy. An artificial lake is created behind the dam.

And energy production also depends on the speed of water means if the speed of water is large then it rotate the turbine faster and increase the production.

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(a) A space vehicle is launched vertically upward from the Earth's surface with an initial speed of vi that is comparable to but

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Energy Conservation Theory,

$(k+v)_i=(k+v)_f \quad \text { (No air resistone)}\\$

$\frac{1}{2} m v_i^2-\frac{G m M_\epsilon}{R_\epsilon}=0-\frac{G m M_\epsilon}{R_\epsilon+h}$

$v_{e x^2}{ }^2-v_i^2=\frac{v_{e^2 R_t} R_t}{R_t t h}\\&\frac{1}{v_{B C^2-v_1^2}^2}=\frac{R_E+h}{v_{e^2 R_E} R_E}\\\\\\h=\frac{R_E V_1^2}{v_{\text {esc }}^2-v_1^{\beta^2}}$

<h3>What is law of energy conservation?</h3>

The principle of energy conservation states that energy is neither created nor destroyed. It may change from one sort to another. Just like the mass conservation rule, the legitimacy of the preservation of energy depends on experimental perceptions; hence, it is an experimental law. The law of preservation of energy, too known as the primary law of thermodynamics

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2 years ago

Which one of the following is the correct option for fill in the

serg [7]

Answer:

mechanical advantage!

Explanation:

The Mechanical advantage of a machine is the factor by which the machine changes the input force.

When a a machine multiplies an input force, that's called a mechanical advantage.

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Defenition of Mechanical Advantage

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Hope this helps! <3

5 0

3 years ago

A 12.0 μF capacitor is charged to a potential of 50.0 V and then discharged through a 265 Ω resistor. A)How long does the capaci

larisa [96]

(a) The time for the capacitor to loose half its charge is 2.2 ms.

(b) The time for the capacitor to loose half its energy is 1.59 ms.

<h3>Time taken to loose half of its charge</h3>

q(t) = q₀e-^(t/RC)

q(t)/q₀ = e-^(t/RC)

0.5q₀/q₀ = e-^(t/RC)

0.5 = e-^(t/RC)

1/2 = e-^(t/RC)

t/RC = ln(2)

t = RC x ln(2)

t = (12 x 10⁻⁶ x 265) x ln(2)

t = 2.2 x 10⁻³ s

t = 2.2 ms

<h3>Time taken to loose half of its stored energy</h3>

U(t) = Ue-^(t/RC)

U = ¹/₂Q²/C

(Ue-^(t/RC))²/2C = Q₀²/2Ce

e^(2t/RC) = e

2t/RC = 1

t = RC/2

t = (265 x 12 x 10⁻⁶)/2

t = 1.59 x 10⁻³ s

t = 1.59 ms

Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.

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2 years ago

A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calcu

galina1969 [7]

Question:

A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

(a)60 (b)90 (c)120

Answer:

(a)5.42 N (b)6.26 N (c)5.42 N

Explanation:

From the question

Length of wire (L) = 2.80 m

Current in wire (I) = 5.20 A

Magnetic field (B) = 0.430 T

Angle are different in each part.

The magnetic force is given by

$F=I \times B \times L \times sin(\theta)$