Answer:
The K.E of the bowling ball right before it hits the ground, K.E = 2450 J
Explanation:
Given data,
The mass of the bowling ball, m = 10 kg
The height of the building, h = 25 m
The total mechanical energy of the body is given by,
E = P.E + K.E
At height 'h' the P.E is maximum and the K.E is zero,
According to the law of conservation of energy, the K.E at the ground before hitting the ground is equal to the P.E at 'h'
Therefore, P.E at 'h'
P.E = mgh
= 10 x 9.8 x 25
= 2450 J
Hence, the K.E of the bowling ball right before it hits the ground, K.E = 2450 J
Answer:
The straight line
Explanation:
All the other stuff is sound waves
Answer:
c
Explanation:
just trying to follow basic grammar.
Answer
the one resister will change because how fast the curcit is going because th rate will change f
Explanation:
Answer:
0 J
Explanation:
The mass is not moving, therefore the kinetic energy is 0.
(I had this same question and the answer is 0)
