Answer:
k = 773.64 N/m
Explanation:
Given:
mass of the pellet, m = 3.56 x 10² kg
Compression in spring, x = 6.61 × 10⁻² m
Height of rise of the pellet, h = 4.83 m
Now, let k be the spring constant
From the concept of conservation of energy, we get
gravitation potential energy acquired by the pellet will be from the energy provided by the spring
thus,
where, g is the acceleration due to the gravity
on substituting the values, we get
or
1.685 = .002178 × k
k = 773.64 N/m
B) the crust is much thinner from the other layers
The distance covered is (4) times (the car's average speed during that time).
I’m not 100% but I was thinking A
Answer:
The angular acceleration is 11.66 rad/s²
Explanation:
Step 1: Given data
Three forces are applied to a solid cylinder of mass 12 kg
F1 = 15 N
F2 = 24 N
F3 = 19 N
R2 = 0.22m
R3 = 0.10m
Step 2: Find the magnitude of the angular acceleration
I = ½mr² = ½ * 12kg * (0.22m)² = 0.29 kg*m²
torque τ = I*α
τ = F2*R2 - F1*R1 = 24N*0.22m - 19N*0.10m = 3.38 N*m
This means
I = ½mr² = 0.29 kg*m²
τ = I*α = 3.38 N*m
OR
0.29 kg*m² * α = 3.38 N*m
α = 11.655 rad/s² ≈11.66 rad/s²
The angular acceleration is 11.66 rad/s²
