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RideAnS [48]
3 years ago
8

What determines the strength of an arrhenius base? give one example each of an aqueous solution of a strong base and an aqueous

solution of a weak base?
Chemistry
1 answer:
IceJOKER [234]3 years ago
6 0
The strength of an Arrhenius base determines percentage of ionization of base and the number of OH⁻ ions formed. 
Strong base completely ionize in water and gives a lot of hydroxide ions (OH⁻), for example sodium hydroxide: NaOH(aq) → Na⁺(aq) + OH⁻(aq).
Weak  base partially ionize in water and gives a few hydroxide ions (OH⁻), for example ammonia: NH₃ + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq).
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If the percent (mass/mass) for a solute is 8% and the mass of the solution is 200 g, what is the mass of solute in solution?
tatyana61 [14]

Answer:

The answer to your question is  16 g

Explanation:

Data

Percent by mass = 8%

Mass of the solution = 200 g

Mass of solute = ?

Formula

Percent by mass = mass of solute / mass of solution x 100

- Solve for mass of solute

  Mass of solute = Percent by mass x mass of solution / 100

- Substitution

   Mass of solute = 8 x 200 / 100

- Simplification

    Mass of solute = 1600 / 100

- Result

    Mass of solute = 16 g

3 0
3 years ago
Read 2 more answers
Your boss tells you that water at 68 F is flowing in a cooling tower loop at a rate of 600 gpm, in an 8-inch inside diameter pip
avanturin [10]

Explanation:

The volumetric flow rate of water will be as follows.

       q = 600 gpm \times \frac{0.000063 m^{3} s^{-1}}{1 gpm}

         = 0.0378 m^{3}/s


    Diameter = 8 in \times \frac{0.0254 m}{1 in}

                   = 0.2032 m

Relation between area and diameter is as follows.

           A = \frac{\pi}{4} \times D^{2}

               = \frac{3.14}{4} \times (0.2032 m)^{2}

               = 0.785 x 0.2032 x 0.2032

               = 0.0324 m^{2}

Also,     q = A × V

or,         V = \frac{q}{A}

                = \frac{0.0378 m^{3}/s}{0.0324 m^{2}}

                = 1.166 m/s

As, viscosity of water = 1 cP = 10^{-3} Pa-s

Density of water = 1000 kg/m^{3}

Therefore, we will calculate Reynolds number as follows.

 Reynolds number = \frac{D \times V \times density}{viscosity}

                                 = \frac{0.2032 m \times 1.166 m/s  \times 1000}{10^{-3}}  

                                = 236931.2

Hence, the flow will be turbulent in nature.

Thus, we can conclude that the Reynolds number is 236931.2 and flow is turbulent.

8 0
2 years ago
Which of the following would NOT diffuse through the plasma membrane by means of simple diffusion?1 oxygen2 glucose3 a steroid h
Mumz [18]

Answer:

Option 2= Glucose

Explanation:

Cell membrane is made up of two phospholipid layers and each contain phosphate head and fatty acid or lipid tails. the head is present between the outer and inner boundaries and tail is present in between. The small non- polar molecules can pass the membrane through simple diffusion. This lipid tail restrict the passage of polar molecules including water soluble substances like glucose. However, transmembranes are present that allow the molecules to inter that are blocked by the tails.

Facilitated diffusion:

it is a type of diffusion in which caries protein without using the cellular energy shuttle the molecules to the cell membrane. Glucose is bind on the carrier protein ,change the shape and transport it from one to another side of membrane. In order to absorb the glucose red blood cells use this kind of diffusion.

Primary active transport:

The cells that are present along small intestine use this type of transport to pump the glucose inside the cell. The primary active transport require energy to transport the glucose inside.

Secondary active transport:

It is another method of transport of glucose into the cell. This method can not use ATP but it is based on concentration gradient of the sodium that provide electro chemical energy for the glucose transport.

5 0
3 years ago
A gas cylinder is filled with 4.00 moles of oxygen gas at 300.0 k. the piston is compressed to yield a pressure of 400.0 kpa. wh
laila [671]
We can use the ideal gas law equation to find the volume of the gas.
PV = nRT
P - pressure - 400 kPa
V - volume 
n - number of moles - 4.00 mol
R - universal gas constant  - 8.314 Jmol⁻¹K⁻¹
T - temperature - 300.0 K
substituting these values in the equation
400 000 Pa x V = 4.00 mol x 8.314 Jmol⁻¹K⁻¹ x 300.0 K 
V = 24.9 dm³
Volume is 24.9 dm³
5 0
3 years ago
What is the name of the aluminum ion? Al–1 Al+2 Al–3 Al+3
Sidana [21]

Most transition metal form more than one cation but aluminum forms the Al3+ cation only.

5 0
3 years ago
Read 2 more answers
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