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hichkok12 [17]
4 years ago
10

How much force is needed to stop a 80-kg football player if he decelerates at 5 m/s2

Physics
1 answer:
kiruha [24]4 years ago
6 0
According to Newton's 2nd law of motion, F =ma = 80x5 = 400N.
You might be interested in
A hockey player has an acceleration of −3.1 m/s2. How long does it take him to come to a complete stop from a speed of 13 m/s?
ddd [48]
Use this formula:

final speed = initial speed + acceleration * time
0 = 13 - 3.1*t, t = 13/3.1 = 4.19354838709677 s = 4.2 seconds, might be enough since ur given 1 decimal place precision

6 0
3 years ago
A spring with a spring constant of 120 J/m2 is fixed to a wall, free to oscillate. On the other end, a ball with a mass of 1500
Neporo4naja [7]

Answer:

A. 4.47 m/s

Explanation:

As the ball oscillates, it mechanical energy, aka the total kinetic and elastics energy stays the same. For the ball to be at maximum speed, its elastic energy i 0 and vice versa. When the ball is at rest, its kinetic energy is 0 and its elastic energy is at maximum at 50 cm, or 0.5 m

1500 g = 1.5 kg

E_e = E_k

kx^2/2 = mv^2/2

120*0.5^2/2 = 1.5*v^2/2

15 = 0.75v^2

v^2 = 15 / 0.75 = 20

v = \sqrt{20} = 4.47 m/s

5 0
3 years ago
Which is a combination of two waves?
RoseWind [281]

Answer: B = surface waves

Explanation:

Transverse and longitudinal waved combined make surface waves.

would'nt mind if you click the brainliest button lol ;)

4 0
3 years ago
Read 2 more answers
A shiny new sports car sits in a parking lot of a car dealership. above is a cargo plane, flying horizontally at 46 m/s. at the
dybincka [34]

First calculate the time it would take for the crate to fall using the formula:

h = v0 t + 0.5 g t^2

110 m = 0 + 0.5 (9.8 m/s^2) t^2

t = 4.74 s

 

The crate is also moving at 46 m/s on with respect to the horizontal surface, therefore distance covered is:

d = (46 m/s) * 4.74 s

d = 217.95 m

 

The crate would fall 217.95 m from the tail of the car. 

6 0
3 years ago
Plz plz help ...i really need steps for this answer
bija089 [108]

Answer:

3.9 seconds

Explanation:

Use constant acceleration equation:

y = y₀ + v₀ t + ½ at²

where y is the final position,

y₀ is the initial position,

v₀ is the initial velocity,

a is the acceleration,

and t is time.

Given:

y = 0 m

y₀ = 15 m

v₀ = 15 m/s

a = -9.8 m/s²

Substituting values:

0 = 15 + 15t + ½ (-9.8) t²

0 = 15 + 15t − 4.9t²

0 = 4.9t² − 15t − 15

Solve with quadratic formula:

t = [ -b ± √(b² − 4ac) ] / 2a

t = [ 15 ± √((-15)² − 4(4.9)(-15)) ] / 2(4.9)

t = [ 15 ± √(225 + 294) ] / 9.8

t = (15 ± √519) / 9.8

t = -0.79 or 3.9

It takes 3.9 seconds for the stone to reach the bottom of the well.

The negative answer is the time it takes the stone to travel from the bottom of the well up to the top of the well.

6 0
3 years ago
Read 2 more answers
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