Calculate the molarity of a solution prepared by dissolving 1.495 moles of lioh in enough water to give a final volume of 750. m
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Answer:
Molecular mass of BHT is 204,2 g/mol
Explanation:
To answer this question you need to know that Freezing-point depression (A colligative property) is the decrease of the freezing point of a solvent on the addition of a non-volatile solute. The formula is:
ΔT = Kf m
Where ΔT is the freezing point depression (5,5°C - 4,880°C = 0,62°C
Kf that is freezing point molar constant of the solvent (5,065°C/m)
And m that is molality (moles of solute/kg of solvent). Replacing:
Knowing you have 100,0g of solvent ≡ 0,1000 kg:
=<em> 0,01224 moles of solute </em> <em>≡ BHT</em>
As grams of BHT are 2,500, molecular mass of BHT is:
<em>204,2 g/mol</em>
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I hope it helps