it should be True unless if I’m wrong
This problem is requiring the balanced chemical equation that takes place when copper hydroxide and potassium sulfate are produced when reacting potassium hydroxide with copper sulfate.
<h3>Balancing chemical equations:</h3>
In chemistry, balancing chemical equations is based on the law of conservation of mass, which demands us to have equal number of atoms on both sides of the chemical equation. This can be accomplished by inserting coefficients in front of the chemical species.
For this particular case, we have potassium hydroxide with copper sulfate on the reactants side, however, copper can be copper (I) or copper (II) as it has 1+ and 2+ as its possible oxidation numbers. In addition, copper hydroxide and potassium sulfate as the products. Hence, we can assume this is all about copper (II) so we can write:

As we can see, potassium, hydrogen and oxygen have two atoms each on the products side, but just one on the reactants side; drawback we can overcome by putting a 2 in front of KOH so as to balance it:

Learn more about balancing chemical equations: brainly.com/question/8062886
It is their properties. it is made up naturally due to the ions
Answer:
The answer to your question is Single replacement
Explanation:
Types of reaction in Chemistry
Synthesis two or more reactants combine to produce one single product
Decomposition one reactant splits producing two or more products
Single replacement One element replaces a similar one in a compound.
Double replacement Two compounds interchange their cations and anions.
Combustion one compound reacts with oxygen to produce carbon dioxide and water.
Reaction given
Fe⁺² + CuSO₄ ⇒ Cu + FeSO₄
This is a single replacement reaction
Answer:
Explanation:
Depression in freezing point is given by:

= Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte like urea)
= freezing point constant = 
m= molality

Weight of solvent (X)= 950 g = 0.95 kg
Molar mass of non electrolyte (urea) = 60.06 g/mol
Mass of non electrolyte (urea) added = ?


Thus
urea was dissolved.