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3 years ago

What type of circuit is illustrated?

Physics

1 answer:

Debora [2.8K]3 years ago

4 0

Answer:

Parallel circuit

Explanation:

A parallel circuit is a closed circuit in which current flows and divide in two or more paths and recombining to complete the circuit, each load (light bulb) receives the fully voltage of the batteries in the circuit.

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Thiết bị nào sau đây không phải là nguồn điện

kumpel [21]

Thiết bị không phải nguồn điện:

Đáp án D

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3 years ago

You are falling off the edge.what should you do to avoid falling..?

Nadya [2.5K]

Lean your shoulders back and your waist forwards. Use your arms as a counter weight.

3 0

3 years ago

Read 2 more answers

A 5.30 m long pole is balanced vertically on its tip. What will be the speed (in meters/second) of the tip of the pole just befo

suter [353]

Answer:

v = 17.66 m/s

Explanation:

As we know that the lower end of the pole is fixed in the ground and it start rotating about that end

so here we can say that the gravitational potential energy of the pole will convert into rotational kinetic energy of the pole about its one end

so we have

$mgL = \frac{1}{2}(\frac{mL^2}{3})\omega^2$

so we have

$\omega = \sqrt{\frac{6g}{L}}$

now we have

$\omega = \sqrt{\frac{6(9.81)}{5.30}}$

$\omega = 3.33 rad/s$

now the speed of the other tip of the pole is given as

$v = \omega L$

$v = (3.33)(5.30) = 17.66 m/s$

8 0

4 years ago

A car moving at 10.0 m/s encounters a bump that has a circular cross-section with a radius of 30.0 m. What is the normal force e

Andrew [12]

Answer:

force at the top will be 388 N which is nearly equal to 389

option (b) is correct

Explanation:

We have given velocity of the moving car v = 10 m/sec

Radius of the circular section r = 30 m

Mass of the passenger m = 60 kg

Acceleration due to gravity $g=9.8m/sec^2$

At the top normal force is given by $noraml\ force=mg-\frac{mv^2}{r}$

So force at top will be $F=60\times 9.8-\frac{60\times 10^2}{30}=388N$

So force at the top will be 388 N which is nearly equal to 389

So option (b) is correct

4 0

3 years ago

Read 2 more answers

A 350-g air track cart is traveling at 1.25 m/s and a 280-g cart traveling in the opposite direction at 1.33 m/s. What is the sp

kumpel [21]

Answer:

The speed of the center of mass of the two carts is 0.103 m/s

Explanation:

It is given that,

Mass of the air track cart, m₁ = 350 g = 0.35 kg

Velocity of air track cart, v₁ = 1.25 m/s

Mass of cart, m₂ = 280 g = 0.28 kg

Velocity of cart, v₂ = -1.33 m/s (it is travelling in opposite direction)

We need to find the speed of the center of mass of the two carts. It is given by the following relation as :

$v_{cm}=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}$

$v_{cm}=\dfrac{0.35\ kg\times 1.25\ m/s+0.28\ kg\times (-1.33\ m/s)}{0.35\ kg+0.28\ kg}$

$v_{cm}=0.103\ m/s$

Hence, this is the required solution.

4 0

3 years ago