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Mamont248 [21]
4 years ago
9

When a base metal is converted into gold - this phenomenon is best described as what?

Chemistry
1 answer:
Naddik [55]4 years ago
5 0

Answer:

Alchemy

Explanation:

Alchemy is the believe that base metals such as a copper, lead etc can be transmuted into gold.

The alchemists were in search of a magical piece that would enable them to make gold from base metals. They called this magical stuff 'the Philosopher's Stone'.

Modern science has discovered that lead can be turned into gold,without applying the methods of alchemy. Nuclear transmutation in particle accelerators can indeed change one element into another.

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The liquid is being heated.
spayn [35]

there should be less liquid at the end of the experiment since heating liquid is an endothermic process, and endothermic processes typically break the bonds between liquids. The applied heat would soon break the bonds that hold the molecules of the liquid together, and evaporation would occur once the temperature is hot enough. Thus, the evaporated water would decrease the volume of the liquid.

6 0
3 years ago
Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 4.3 g of hexane is mi
Ilya [14]

Answer:

We can produce 6.20 grams of CO2

Explanation:

Step 1: Data given

Mass of hexane = 4.3 grams

Molar mass of hexane = 86.18 g/mol

Mass of oxygen = 7.14 grams

Molar mass of oxygen = 32.0 g/mol

Step 2: The balanced equation

2C6H14 + 19O2 → 12CO2 + 14H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles hexane = 4.3 grams / 86.18 g/mol

Moles hexane = 0.0499 moles

Moles oxygen = 7.14 grams / 32.0 g/mol

Moles oxygen = 0.2231 moles

Step 4: Calculate the limiting reactant

For 2 moles hexane we need 19 moles O2 to produce 12 moles CO2 and 14 moles H2O

Oxygen is the limiting reactant. It will completely be consumed ( 0.2231 moles). Hexane is in excess. There will react 2/19 * 0.2231 = 0.02348 moles

There will be porduced 12/19 * 0.2231 = 0.1409 moles CO2

Step 5: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.1409 moles * 44.01 g/mol

Mass CO2 = 6.20 grams

We can produce 6.20 grams of CO2

5 0
3 years ago
The liquid inside the cell is called
rodikova [14]

Answer:

The cytoplasm

Explanation:

Cytoplasm is the gelatinous liquid that fills the inside of a cell. It is composed of water, salts, and various organic molecules. Some intracellular organelles, such the nucleus and mitochondria, are enclosed by membranes that separate them from the cytoplasm.

Pls mark as brainliest

hope this helps:)

5 0
3 years ago
What is the mass of 5 moles of Fe2O?
Elenna [48]

Explanation:

1 miole of Fe2O is 6.22 × 10^-23

5mole of Fe2O = 5×6.22×10^-23

=31.1×10^-23

8 0
3 years ago
The densities of gases a, b, and c at stp are 1.25 g/l, 2.86 g/l and 0.714 g/l, respectively. calculate the molar mass of each s
kicyunya [14]
The  molar  mass  of    a, b and  c at  STP is calculated  as  below

At  STP  T  is always=   273 Kelvin and ,P= 1.0 atm 

by  use of  ideal  gas  equation  that  is  PV =nRT
n(number   of moles) = mass/molar mass  therefore  replace   n  in  the  ideal   gas  equation

that  is Pv = (mass/molar mass)RT
multiply  both side  by molar  mass  and  then  divide  by  Pv  to  make  molar mass the  subject of the  formula

that is  molar  mass =  (mass x RT)/ PV

 density is always = mass/volume

therefore  by  replacing  mass/volume  in   the equation  by  density the equation
molar  mass=( density  xRT)/P  where R  =  0.082 L.atm/mol.K

the  molar mass  for  a
= (1.25 g/l  x0.082 L.atm/mol.k  x273k)/1.0atm = 28g/mol

the molar  mass of b
=(2.86g/l  x0.082L.atm/mol.k   x273  k) /1.0  atm  = 64  g/mol

the molar  mass of c

=0.714g/l  x0.082  L.atm/mol.K  x273 K) 1.0atm= 16 g/mol

therefore  the 
   gas  a  is  nitrogen N2   since 14 x2= 28 g/mol
   gas b =SO2  since  32 +(16x2)= 64g/mol
  gas c =   methaneCH4  since  12+(1x4) = 16 g/mol


8 0
3 years ago
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