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AlladinOne [14]
3 years ago
7

A coil with internal resistance can be modeled as a resistor and an ideal inductor in series. Assume that the coil has an intern

al resistance of 2.00 omega and an inductance of 480 mH. A 1.60 1.60 MuF capacitor is charged to 24.0 V and is then connected across the coil.
(a) What is the initial voltage across the coil? V
(b) How much energy is dissipated n the circuit before the oscillations die out? mJ
(c) What is the frequency of oscillation of the circuit? (Assume the internal resistance is sufficiently small that it has no impact on the frequency of the circuit.) Hz
(d) What is the quality factor of the circuit?
Physics
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:The impedance per phase is 1.25H. This was calculated using the ... the complex power generated is 3.4kw. The full solution can be found below.

Explanation:

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Answer it will move slower:

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How is distance related to force in this experiment to mass
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3 years ago
A 2.8 kg grinding wheel is in the form of a solid cylinder of radius 0.1 m. a) What constant torque will bring it from rest to a
kogti [31]

Answer:

a) τ =  0.672 N m , b) θ = 150 rad , c) W = 100.8 J

Explanation:

a) for this part let's start by finding angular acceleration, when the angular velocity stops it is zero (w = 0)

       w = w₀ + α t

       α = -w₀ / t

       α = 120 / 2.5

       α = 48 rad / s²

The moment of inertia of a cylinder is

       I = ½ M R²

Let's calculate the torque

      τ = I α

      τ = ½ M R² α

      τ = ½ 2.8 0.1² 48

      τ =  0.672 N m

b) we look for the angle by kinematics

      θ = w₀ t + ½ α t2

      θ = ½ α t²

      θ = ½ 48 2.5²

      θ = 150 rad

c) work in angular movement

      W = τ θ

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      W = 100.8 J

7 0
3 years ago
In a very busy off-campus eatery one chef sends a 201 g broccoli-tomato-pickle-onion-mushroom pizza sliding down the counter fro
Murrr4er [49]

Answer:

The correct answer is:

(A) to the left

(B) at speed -0.8725 m/s

Explanation:

The given values are:

Plate 1:

Mass,

m₁ = 201 g

Velocity,

v₁ = +1.79 m/s

Plate 2:

Mass,

m₁ = 335 g

Velocity,

v₁ = -2.47 m/s

According to the conservation of momentum, we get

⇒  m_1v_1+m_2v_2=(m_1+m_2)v

then,

⇒  v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

On substituting the values, we get

⇒     =\frac{201\times 1.79+335\times (-2.47)}{201+335}

⇒     =\frac{359.79-827.45}{536}

⇒     =\frac{-467.66}{536}

⇒     =-0.8725 (to the left)

3 0
2 years ago
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