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AlladinOne [14]
3 years ago
7

A coil with internal resistance can be modeled as a resistor and an ideal inductor in series. Assume that the coil has an intern

al resistance of 2.00 omega and an inductance of 480 mH. A 1.60 1.60 MuF capacitor is charged to 24.0 V and is then connected across the coil.
(a) What is the initial voltage across the coil? V
(b) How much energy is dissipated n the circuit before the oscillations die out? mJ
(c) What is the frequency of oscillation of the circuit? (Assume the internal resistance is sufficiently small that it has no impact on the frequency of the circuit.) Hz
(d) What is the quality factor of the circuit?
Physics
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:The impedance per phase is 1.25H. This was calculated using the ... the complex power generated is 3.4kw. The full solution can be found below.

Explanation:

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3. Suppose that you have an electrically charged stick. If you divide the stick in half, each half will have half the original c
FrozenT [24]

Answer:

No, you can't keep on dividing the charge forever.

Explanation:

No, you can't keep on dividing the charge in that manner forever because the total charge of the stick is an integer multiples of individual units known as an elementary charge, <em>which is the electron (e) charge (e = 1.602x10⁻¹⁹C)</em>.

Therefore the limit of the division of the original charge will be the electron charge since it is the smallest charge that can exist freely.  

I hope it helps you!  

8 0
3 years ago
What is the global food supply
Sophie [7]

Answer:

The food supply chain comprises all the stages that food products go through, from production to consumption

Explanation:

7 0
2 years ago
To navigate, a porpoise emits a sound wave that has a wavelength of 3.3 cm. The speed at which the wave travels in seawater is 1
dedylja [7]

Answer:

2.2\times 10^{-5} s

Explanation:

We are given that  

The wavelength of sound wave=\lambda=3.3 cm=3.3\times 10^{-2}m/s

1 cm/s=10^{-2}m/s

Speed of sound wave,v=1522 m/s

We have to find the period of the wave.

We know that

Frequency=\nu=\frac{v}{\lambda}

Using the formula

Frequency =\frac{1522}{3.3\times 10^{-2}}=4.6\times 10^{4} Hz

Time period=\frac{1}{4.6\times 10^4}=0.22\times 10^{-4}\times \frac{10}{10^1}=2.2\times 10^{-4-1}=2.2\times 10^{-5}s

Using identity:\frac{a^x}{a^y}=a^{x-y}

Hence, the time period of the wave=2.2\times 10^{-5} s

4 0
3 years ago
While escaping from a building in which a fire is burning, 40 people pass through a smoky
kherson [118]

my bad  i clicked the wrong question to do sorry i wish i could help but im dumb lol

8 0
4 years ago
A particle's position is given by x = 7.00 - 9.00t + 3t2, in which x is in meters and t is in seconds. (a) What is its velocity
spin [16.1K]

x(t)=7.00\,\mathrm m-\left(9.00\dfrac{\rm m}{\rm s}\right)t+\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2

a. The particle has velocity at time t,

\dfrac{\mathrm dx(t)}{\mathrm dt}=-9.00\dfrac{\rm m}{\rm s}+\left(6\dfrac{\rm m}{\mathrm s^2}\right)t

so that after t=1\,\mathrm s it will have velocity \boxed{-3.00\dfrac{\rm m}{\rm s}}.

b. The sign of the velocity is negative, so it's moving in the negative x direction.

c. Its speed is 3.00 m/s.

d. The particle's velocity changes according to

\dfrac{\mathrm d^2x(t)}{\mathrm dt^2}=6\dfrac{\rm m}{\mathrm s^2}

which is positive and indicates the velocity/speed of the particle is increasing.

e. Yes. The velocity is increasing at a constant rate. Solving for \dfrac{\mathrm dx(t)}{\mathrm dt}=0 is trivial; this happens when \boxed{t=1.50\,\mathrm s}.

f. No, the velocity is positive for all t beyond 1.50 s.

5 0
3 years ago
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