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Kaylis [27]
3 years ago
7

What is the name of an immune system response to a substance in food?

Chemistry
1 answer:
poizon [28]3 years ago
3 0

Answer:

The adaptive (also called humoral or specific) immune system is typically only involved in immune responses to bacteria, bacterial toxins and virus antigens. It involves the production of antibodies (also called immunoglobulins) against a specific target. The target of an antibody is called an antigen.

You might be interested in
On a clear day at sea level, with a temperature of 25 °C, the partial pressure of N2 in air is 0.78 atm and the concentration of
joja [24]

Answer : The partial pressure of nitrogen gas is, 2.94 atm

Explanation:

According top the Henry's Law, the concentration of a gas in a liquid is directly proportional to the partial pressure of the gas.

C\propto P

C=K_H\times P

K_H is Henry's constant.

or,

\frac{C_1}{C_2}=\frac{P_1}{P_2}

where,

C_1 = initial concentration of gas = 5.3\times 10^{-4}M

C_2 = final concentration of gas = 2.0\times 10^{-3}M

P_1 = initial partial pressure of gas = 0.78 atm

P_2 = final partial pressure of gas = ?

Now put all the given values in the above formula, we get the final partial pressure of the gas.

\frac{5.3\times 10^{-4}M}{2.0\times 10^{-3}M}=\frac{0.78atm}{P_2}

P_2=2.94atm

Therefore, the partial pressure of nitrogen gas is, 2.94 atm

5 0
4 years ago
Automobile airbags contain solid sodium azide, NaN 3 , that reacts to produce nitrogen gas when heated, thus inflating the bag.
Yuri [45]

<u>Answer:</u> The value of work for the system is -935.23 J

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of sodium azide = 16.5 g

Molar mass of sodium azide = 65 g/mol

Putting values in above equation, we get:

\text{Moles of sodium azide}=\frac{16.5g}{65g/mol}=0.254mol

The given chemical equation follows:

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

By Stoichiometry of the reaction:

2 moles of sodium azide produces 3 moles of nitrogen gas

So, 0.254 moles of sodium azide will produce = \frac{3}{2}\times 0.254=0.381mol of nitrogen gas

To calculate volume of the gas given, we use the equation given by ideal gas, which follows:

PV=nRT

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = ?

T = Temperature of the gas = 22^oC=[22+273]K=295K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of nitrogen gas = 0.381 moles

Putting values in above equation, we get:

1.00atm\times V=0.381mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 295K\\\\V=\frac{0.381\times 0.0821\times 295}{1.00}=9.23L

To calculate the work done for expansion, we use the equation:

W=-P\Delta V

We are given:

P = pressure of the system = 1atm=1.01325\times 10^5Pa     (Conversion factor:  1 atm = 101325 Pa)

\Delta V = change in volume = 9.23L=9.23\times 10^{-3}m^3     (Conversion factor:  1m^3=1000L )

Putting values in above equation, we get:

W=-1.01325\times 10^5Pa\times 9.23\times 10^{-3}m^3\\\\W=-935.23J

Hence, the value of work for the system is -935.23 J

7 0
4 years ago
Please help!!! (im really bad at chemistry)
Lubov Fominskaja [6]

Answer:

1000ml/1L

Explanation:

8 0
3 years ago
What is the minimum (non-zero) thickness of a benzene (n = 1.501) thin film that will result in constructive interference when v
ad-work [718]

Explanation:

At each reflecting surface (benzene and glass) there will be 180 degree phase change.

Now, for constructive interference the optical path in benzene is \lambda.

Formula to calculate thickness of a benzene thin film is as follows.

     Optical path length through benzene (\lambda) = 2 \times n \times d

Hence, substituting the given values into the above formula as follows.

    Optical path length through benzene = 2 \times n \times d

                   d = \frac{\text{Optical path length through benzene}}{2 \times n}

                       = \frac{\lambda}{2 \times n}  

                       = \frac{615 \times 10^{-9}}{2 \times 1.501}   (as 1 nm = 10^{-9}m

                       = 204.9 m          

Thus, we can conclude that minimum thickness of benzene is 204.9 m.

4 0
3 years ago
Can somebody please give me an answer for this question that doesn't consist of building or construction?
zavuch27 [327]

Answer:

to build a house you need land and people

Explanation:

4 0
3 years ago
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