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Musya8 [376]
3 years ago
5

Suppose a 4000 kg elephant is hoisted 20m above Earth's surface. What will be the elephant's gravitational potential energy?

Physics
1 answer:
inna [77]3 years ago
8 0
We know, U = m * g * h
U = 4000 * 9.8 * 20
U = 784000 J

In short, Your Answer would be: 784000 J or 784 KJ

Hope this helps!
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Calculate the volume of the metal required to make a hemisperical bowl with internal and external radii 8.4cm and 9.1cm respecti
ioda
External = R
Internal = r
Volume of hemisperical = 2/3 π(R³-r³)
V= 2/3 π(9.1³ - 8.4³)
V= 336.9 cm³
4 0
3 years ago
You have given a power supply, copper wire, and an iron nail. What should you do to decrease the strength of the electro magnet?
Shkiper50 [21]
If you wrap some of the wire around the nail in one direction and some of the wire in the other direction, the magnetic fields from the different sections fight each other and cancel out, reducing the strength of your magnet.
8 0
3 years ago
3) If a ball launched at an angle of 10.0 degrees above horizontal from an initial height of 1.50 meters has a final horizontal
Irina-Kira [14]

Answer:

35.6 m

Explanation:

3 0
3 years ago
If it takes 50.0 seconds to lift 10.0 Newtons of books to a height of 7.0
Ilya [14]
Work of the force = 10 N

Time required for the work = 50 sec

Height = 7 m

We are given with the value of work and time in the question.

Substitute the values in the formula of power and then you'll get the power required.

We know that,

w = Work

p = Power

t = Time

By the formula,

Given that,
Work (w) = 7 m = 70 Joules
Time (t) = 50 sec
Substituting their values,

p = 70/50

p = 1.4 watts

Therefore, the power required is 1.4 watts.

Hope it helps!
3 0
3 years ago
An automobile with an initial speed of 4.92 m/s accelerates uniformly at the rate of 3.2 m/s2 . Find the final speed of the car
Rudik [331]

Answer:19.32 m/s

Explanation:

Given

initial speed of car(u)=4.92 m/s

acceleration(a)=3.2 m/s^2

Speed of car after 4.5 s

using equation of motion

v=u+at

v=4.92+3.2\times 4.5=4.92+14.4

v=19.32 m/s

Displacement of the car after 4.5 s

v^2-u^2=2as

19.32^2-4.92^2=2\times 3.2\times s

349.05=2\times 3.2\times s

s=54.54 m

4 0
3 years ago
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