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shtirl [24]
3 years ago
13

A particle starts at the origin and moves away from it in a straight line. After 1.6 seconds, it is 12.8 meters from the origin.

It then reverses direction due to a force field with a like charge. After 3.8 seconds total, the particle is at −9.23 m. What is the average velocity of the particle? 3.8 m/s −5.8 m/s −2.4 m/s 13.8 m/s
Physics
1 answer:
Digiron [165]3 years ago
4 0

Answer:

Average velocity of the particle is-2.4 m/s

Explanation:

Average velocity is defined as the total velocity divided by the total time. It is given  by the equationv_av= \frac{displacement}{(total time taken)}

In the given problem the particle starts from origin, travels 12.8 m and then reverses direction and travels till -9.23 m within a total time of 3.8 seconds.

Displacement is defines as the shortest distance between initial and final point.  

Here displacement = - 9.23 m

total time=3.8 s

v_av=-9.23/3.8=-2.4 m/s

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