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Darina [25.2K]
4 years ago
10

You are explaining to friends why astronauts feel weightless orbiting in the space shuttle, and they respond that they thought g

ravity was just a lot weaker up there. Convince them and yourself that it isn't so by calculating how much weaker gravity is 400 km above the Earth's surface.
Physics
1 answer:
bezimeni [28]4 years ago
6 0

Answer:

It's only 1.11 m/s2 weaker at 400 km above surface of Earth

Explanation:

Let Earth radius be 6371 km, or 6371000 m. At 400km above the Earth surface would be 6371 + 400 = 6771 km, or 6771000 m

We can use Newton's gravitational law to calculate difference in gravitational acceleration between point A (Earth surface) and point B (400km above Earth surface):

g = G\frac{M}{r^2}

where G is the gravitational constant, M is the mass of Earth and r is the distance form the center of Earth to the object

\frac{g_B}{g_A} = \frac{GM/r^2_B}{GM/r^2_A}

\frac{g_B}{g_A} = \left(\frac{r_A}{r_B}\right)^2

\frac{g_B}{g_A} = \left(\frac{6371000}{6771000}\right)^2

\frac{g_B}{g_A} = 0.94^2 = 0.885

g_B = 0.885 g_A

So the gravitational acceleration at 400km above surface is only 0.885 the gravitational energy at the surface, or 0.885*9.81 = 8.7 m/s2, a difference of (9.81 - 8.7) = 1.11 m/s2.

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Answer:

Both equilibrium price and quantity will increase.

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Determine the velocity (in m/s) of the object at 10seconds. Include a numerical answer accurate to the first decimal place. If n
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Answer:

v = 0.5 [m/s]

Explanation:

In order to determine the speed in such a time interval, we must calculate the slope between the last two positions.

The slope of a line is determined by the following mathematical expression.

P₂ = point 2 = (12,12) = (x₂,y₂)

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Now using the slope:

m =\frac{y_{2} -y_{1} }{x_{2} -x_{1} } \\m = \frac{12-9}{12-6}\\m = 0.5

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v = 0.5 [m/s]

8 0
3 years ago
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Black_prince [1.1K]
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The Sun delivers an average power of 1150 W/m2 to the top of the Earth’s atmosphere. The permeability of free space is 4π × 10−7
My name is Ann [436]

Answer:

E=930.84 N/C

Explanation:

Given that

I = 1150 W/m²

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E= C B

C=speed of light

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Power  P = I A

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I=\dfrac{CB^2}{2\mu_0}

I=\dfrac{CE^2}{2\mu_0 C^2}

E=\sqrt{{2I\mu_0 C}}

E=\sqrt{{2\times 1150\times 4\pi \times 10^{-7}(2.99792\times 10^8)}}

E=930.84 N/C

Therefore answer is 930.84 N/C

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Answer:

D

Explanation:

4 0
3 years ago
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